AP Chem Unit 8 Review
Quiz
•
Chemistry
•
12th Grade
•
Practice Problem
•
Hard
+2
Standards-aligned
Charles Martinez
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20 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
At equilibrium the concentration of all species in the reaction is _________.
Tags
NGSS.HS-PS1-6
NGSS.HS-PS1-7
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Increasing the temperature on a ________ reaction will increase the concentration of products.
Tags
NGSS.HS-PS1-5
3.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Silver chromate, Ag2CrO4, has a Ksp of 4.0 x 10-12. What is the concentration of silver ions in a saturated solution.
2.0 x 10-4 M
1.0 x 10-4 M
2.0 x 10-12 M
1.0 x 10-12 M
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
When the chemical reaction A + B ↔ C+ D is at equilibrium,
Tags
NGSS.HS-PS1-6
5.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
H2(g) + I2(g) ⇄ 2 HI(g)
At 450oC, 2.0 moles each of H2(g), I2(g), and HI(g) are combined in a 1.0 L rigid container. The value of Kc at 450oC is 50. Which of the following will occur as the system moves toward equilibrium?
More H2(g) and I2(g) will form because Q<K.
More HI(g) will form because Q<K
More HI will form because Q>K
No net reaction will occur, because the number of molecules is the same on both sides of the equation.
Tags
NGSS.HS-PS1-5
6.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
PCl3(g) + Cl2(g) ⇄ PCl5(g) Kc = 1.5
At a certain point in time, a 1.00 L rigid reaction vessel contains 1.5 mol of PCl3(g), 1.0 mol of Cl2(g), and 3.0 mol of PCl5(g). Which of the following statements is true?
The equilibrium will shift to the right since there are less moles from the equation.
The pressure of PCl3 will increase because Q > Kc.
The pressure of PCl3 will decrease because Q < Kc.
The pressure will decrease because Q > Kc.
Tags
NGSS.HS-PS1-7
7.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
In which of the following systems would the number of moles of the substances present at equilibrium NOT be shifted by a change in the volume of the system at constant temperature?
CO(g) + NO(g) ↔ CO2(g) + ½ N2(g)
N2(g) + 3 H2(g) ↔ 2 NH3(g)
N2(g) + 2 O2(g) ↔ 2 NO2(g)
NO(g) + O3(g) ↔ NO2(g) + O2(g)
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