Word Problems Involving Work Energy Theorem

45 J of work were done on the object that moved 5 meters. How much force was applied to the object?

• 8 N

• 225 N

• 9 N

• 0 N

Tags

NGSS.HS-PS2-1

The net work done by a net force acting on an object is equal to the change in the kinetic energy of the object.

• Force-Work Theorem
• Work-Kinetic Energy Theorem
• Force-Kinetic Energy Theorem
• Work-Force Theorem

What is the ΔKE of a baseball hit with a force of 6000 N that travels 120 m across the field?

• 6000J

• 43560000J

• 720000J

• 50J

Tags

NGSS.HS-PS3-1

A 10.0 kg box is accelerated from 2.0 m/s to 4.0 m/s. What is the amount of work needed to accelerate the box?

• 50 J

• 60 J

• 20 J

• 45 J

Tags

NGSS.HS-PS2-1

NGSS.HS-PS3-1

When my velocity triples, my kinetic energy increases by ______ times.

• 9
•  3 
• 1.5
• 4.5

Calculate the force necessary to move a 1000 kg car from rest to 25 m/s in 130 m.

• 1.274 x 10⁶ N

• 25,0000 N

• 2403.85 N

• 3.25 x 10⁶ N

Tags

NGSS.HS-PS2-1

True or false: the net work done on a body is equal to its change in kinetic energy.

• True
• False

Tags

NGSS.HS-PS3-1

What does work equal when the final change in kinetic energy equals 20,000 J?

• 0J

• 2041J

• 20,000J

• 4164931J

Which equation would you use to find distance when you know mass, V_f, V_i, and Force?

• W = KE_f - KE_i

• F⋅d = KE

• W = 1/2 mv_f² - 1/2 mv_i²

• F⋅d = 1/2 mv_f² - 1/2 mv_i²

Tags

NGSS.HS-PS2-1

A 12 kg book is pushed from rest to a final velocity of 10 m/s. The book travels 6 m. How much force was the book pushed with?

• 600 N

• 100 N

• 200 N

• 1200 N

Tags

NGSS.HS-PS2-1