
Uniform Circular Motion
Quiz
•
Physics
•
11th Grade
•
Practice Problem
•
Medium
Standards-aligned
KAILEY MARTIN
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8 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The term centripetal means…….
Circular Motion
Center-seeking
Center-Fleeing
Constant Motion
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The direction of acceleration and the centripetal force is always towards….
The center
Tangential
Outward
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
4. What is the direction of the acceleration and velocity of the object traveling clockwise below?
Acceleration is towards the center, velocity is tangential.
Acceleration is tangential, velocity is towards the center.
Both acceleration and velocity are towards the center.
Both acceleration and velocity are tangential.
Tags
NGSS.HS-PS2-1
4.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
5. A ball with a mass of 2 kg is attached to a string and is swung in a horizontal circle with a radius of 0.5 meters. If the ball moves with a tangential velocity of 4 m/s, what is the centripetal force on the ball?
8 N
16 N
32 N
64 N
Answer explanation
Centripetal force (Fc) is calculated using the formula Fc = (mv^2)/r. Here, m = 2 kg, v = 4 m/s, and r = 0.5 m. Thus, Fc = (2 * 4^2) / 0.5 = 32 N. Therefore, the correct answer is 32 N.
Tags
NGSS.HS-PS2-1
5.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
6. A race car with mass 500 kg drives around a track that has a radius of 25 m. If the car experiences a net centripetal force of 50 N, what is the velocity of the race car?
1 m/s
1.6 m/s
2.2 m/s
4.5 m/s
Answer explanation
To find the velocity, use the formula F = mv^2/r. Rearranging gives v = sqrt(F*r/m). Plugging in F = 50 N, r = 25 m, and m = 500 kg results in v = sqrt(50*25/500) = 2 m/s, which is the correct answer.
Tags
NGSS.HS-PS2-1
6.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
7. A hockey puck with mass 3.5 kg is swung in a horizontal circle. If the puck has a tangential velocity of 5 m/s and experiences a net centripetal force of 28 N, what is the puck's distance from the center of the circular path?
2.7m
3.1 m
1.6 m
4.5 m
Answer explanation
To find the distance from the center, use the formula for centripetal force: F = mv^2/r. Rearranging gives r = mv^2/F. Substituting m = 3.5 kg, v = 5 m/s, and F = 28 N results in r = (3.5 * 25) / 28 = 2 m.
Tags
NGSS.HS-PS2-1
7.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
8. A truck is traveling around a circular turn with a tangential velocity of 40 m/s. If the radius of the turn is 20 m and the truck experiences a centripetal force of 18,000 N, what is the mass of the truck?
200 kg
225 kg
500 kg
275 kg
Answer explanation
To find the mass of the truck, use the formula for centripetal force: F = mv^2/r. Rearranging gives m = Fr/v^2. Substituting F = 18000 N, v = 40 m/s, and r = 20 m results in m = 500 kg, which is the correct answer.
Tags
NGSS.HS-PS2-1
8.
CLASSIFICATION QUESTION
5 mins • 1 pt
Organize these options into the right categories
Groups:
(a) Stays the Same
,
(b) Changes
The distance from the center of the circular path
The speed of the object in uniform circular motion
The velocity of the object
The mass of the object
The acceleration of the object
The direction of the centripetal force
The direction of the object's motion
Tags
NGSS.HS-PS2-1
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