Uniform Circular Motion

Uniform Circular Motion

11th Grade

8 Qs

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Uniform Circular Motion

Uniform Circular Motion

Assessment

Quiz

Physics

11th Grade

Practice Problem

Medium

NGSS
HS-PS2-1

Standards-aligned

Created by

KAILEY MARTIN

Used 8+ times

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8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The term centripetal means…….

Circular Motion

Center-seeking

Center-Fleeing

Constant Motion

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The direction of acceleration and the centripetal force is always towards….

The center

Tangential

Outward

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

4. What is the direction of the acceleration and velocity of the object traveling clockwise below?

Acceleration is towards the center, velocity is tangential.

Acceleration is tangential, velocity is towards the center.

Both acceleration and velocity are towards the center.

Both acceleration and velocity are tangential.

Tags

NGSS.HS-PS2-1

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

5. A ball with a mass of 2 kg is attached to a string and is swung in a horizontal circle with a radius of 0.5 meters. If the ball moves with a tangential velocity of 4 m/s, what is the centripetal force on the ball?

8 N

16 N

32 N

64 N

Answer explanation

Centripetal force (Fc) is calculated using the formula Fc = (mv^2)/r. Here, m = 2 kg, v = 4 m/s, and r = 0.5 m. Thus, Fc = (2 * 4^2) / 0.5 = 32 N. Therefore, the correct answer is 32 N.

Tags

NGSS.HS-PS2-1

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

6. A race car with mass 500 kg drives around a track that has a radius of 25 m. If the car experiences a net centripetal force of 50 N, what is the velocity of the race car?

1 m/s

1.6 m/s

2.2 m/s

4.5 m/s

Answer explanation

To find the velocity, use the formula F = mv^2/r. Rearranging gives v = sqrt(F*r/m). Plugging in F = 50 N, r = 25 m, and m = 500 kg results in v = sqrt(50*25/500) = 2 m/s, which is the correct answer.

Tags

NGSS.HS-PS2-1

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

7. A hockey puck with mass 3.5 kg is swung in a horizontal circle. If the puck has a tangential velocity of 5 m/s and experiences a net centripetal force of 28 N, what is the puck's distance from the center of the circular path?

2.7m

3.1 m

1.6 m

4.5 m

Answer explanation

To find the distance from the center, use the formula for centripetal force: F = mv^2/r. Rearranging gives r = mv^2/F. Substituting m = 3.5 kg, v = 5 m/s, and F = 28 N results in r = (3.5 * 25) / 28 = 2 m.

Tags

NGSS.HS-PS2-1

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

8. A truck is traveling around a circular turn with a tangential velocity of 40 m/s. If the radius of the turn is 20 m and the truck experiences a centripetal force of 18,000 N, what is the mass of the truck?

200 kg

225 kg

500 kg

275 kg

Answer explanation

To find the mass of the truck, use the formula for centripetal force: F = mv^2/r. Rearranging gives m = Fr/v^2. Substituting F = 18000 N, v = 40 m/s, and r = 20 m results in m = 500 kg, which is the correct answer.

Tags

NGSS.HS-PS2-1

8.

CLASSIFICATION QUESTION

5 mins • 1 pt

Organize these options into the right categories

Groups:

(a) Stays the Same

,

(b) Changes

The distance from the center of the circular path

The speed of the object in uniform circular motion

The velocity of the object

The mass of the object

The acceleration of the object

The direction of the centripetal force

The direction of the object's motion

Tags

NGSS.HS-PS2-1