Stoichiometry Test

Stoichiometry Test

10th - 12th Grade

10 Qs

quiz-placeholder

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Stoichiometry Test

Stoichiometry Test

Assessment

Quiz

Chemistry

10th - 12th Grade

Hard

NGSS
HS-PS1-7

Standards-aligned

Created by

Charles Martinez

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A balanced chemical equation allows one to determine the

mole ratio of any two substances in the reaction.

energy released in the reaction.

electron configuration of all the elements in the reaction.

mechanism involved in the reaction.

Tags

NGSS.HS-PS1-7

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The coefficients in a chemical equation represent the

masses, in grams, of all reactants and products.

relative numbers of moles of reactants and products.

number of atoms in each compound in a reaction.

number of valence electrons involved in the reaction.

Tags

NGSS.HS-PS1-7

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the equation 2Al2O3 ----> 4Al + 3O2, what is the mole ratio of aluminum to oxygen?

10:6

3:4

2:3

4:3

Tags

NGSS.HS-PS1-7

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Fewer steps are required to solve stoichiometric problems when

the reactant is given in grams and the product is sought in grams.

the reactant is given in moles and the product is sought in moles.

the reactant is given in grams and the product is sought in moles.

the reactant is given in moles and the product is sought in grams.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

All stoichiometry problems must include

a gram to mole conversion factor.

a mole to gram conversion factor.

a mole to gram & a gram to mole conversion factor.

a mole ratio.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A gram to gram stoichiometry problem must include

a gram to mole conversion factor

a mole to gram conversion factor

a gram to mole & a mole to gram conversion factor.

two gram to mole conversion factors.

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

One important component of gasoline mixtures is octane. The combustion of octane is represented in this equation:

2C8H18 + 25O2 ----> 16CO2 + 18H2O. How many moles of oxygen are required to burn 0.40 moles of octane?

5 moles O2

7.5 moles O2

10 moles O2

25 moles O2

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