Simple Harmonic Motion Review

A pair of trapeze performers at the circus is swinging from ropes attached to a large elevated platform. Suppose that the performers can be treated as a simple pendulum with a length of 16 m. Determine the period for one complete back and forth cycle.

• 2 sec
• 12 sec
• 8 sec
• 10 sec

A pendulum is 0.75 meters long and has a period of 4.17 seconds. The Pendulum is on an unknown planet.  What is the gravity of the Unknown Planet?

• 9.8
• 3.4
• 1.7
• Greater than 9.8

Tags

NGSS.HS-PS2-4

If the length of a simple pendulum is doubled, its period will: 

• halve 
• increase by a factor of sqrt(2) 
• decrease by a factor of sqrt(2)
• double 

For a system in simple harmonic motion, which of the following is the time required to complete a cycle of motion?

• amplitude
• period
• frequency
• revolution

Based on your findings, which equation could best describe the pendulum’s period?

• A

• B

• C

• D

A 550 kg mass is in simple harmonic motion on a spring, solve for the displacement if the spring constant value for the spring is 98100 N/m and the restoring force is -981 N.  

• 100 m
• .01 m
• 9.62 x 10^{8 m}

A simple harmonic oscillator takes 4.8 s to undergo five complete vibrations. What is the frequency of 1cycle? 

• 1.04 s
• 4.8 s
• 1/4.8 s

Tags

NGSS.HS-PS4-1

A simple harmonic oscillator takes 4.8 s to undergo five complete vibrations. What is the period (T) of 1 cycle?

• 4.8 s
• .96 s
• 9.8 s