13 Sine wave quantities (A)
Authored by Paul Ward
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8 questions
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1.
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30 sec • 1 pt
1. A sine wave has a peak voltage of 100V; calculate the RMS value. (1dp)
(a)
2.
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30 sec • 1 pt
2. A sine wave has a peak voltage of 100V; calculate the average value. (1dp)
(a)
Answer explanation
Average Voltage = Peak Voltage × 0.636
Average Voltage= 100 × 0.636= 63.6 Volts
3.
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30 sec • 1 pt
3.A sine wave has a peak voltage of 565.7V; calculate the RMS value.
(Nearest whole number)
(a)
4.
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30 sec • 1 pt
4.A sine wave has a peak voltage of 565.7V; calculate the average value.
(Nearest whole number)
(a)
Answer explanation
Average Voltage = Peak Voltage × 0.636
Average Voltage= 565.7 × 0.636= 359.79 Volts
∴ 360 volts to the nearest whole number
5.
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30 sec • 1 pt
5. A sine wave has a peak voltage of 90V; calculate the RMS value. (2dp)
(a)
6.
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30 sec • 1 pt
6.A sine wave has a peak voltage of 90V; calculate the average value.
(2dp)
(a)
Answer explanation
Average Voltage = Peak Voltage × 0.636
Average Voltage= 90 × 0.636= 57.24 Volts
∴ The answer is 57.24 volts
7.
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30 sec • 1 pt
7.A sine wave has an RMS voltage of 40V; calculate the peak value. (1dp)
(a)
Answer explanation
Peak Voltage =RMS Voltage/0.707
or
Peak Voltage=RMS Voltage × √2
40∕0.707 = 56.6 Volts (1dp)
40 × √2 = 56.6 Volts (1dp)
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