13 Sine wave quantities (A)

13 Sine wave quantities (A)

Vocational training

8 Qs

quiz-placeholder

Similar activities

Sisih 2

Sisih 2

KG - University

10 Qs

Avoiding Electrocution Hazards

Avoiding Electrocution Hazards

10th Grade

10 Qs

SSC Topic C022

SSC Topic C022

9th Grade

7 Qs

303 #3 – Protective Devices

303 #3 – Protective Devices

KG - University

10 Qs

Chapter 7 (2) : Electrical Installation Systems

Chapter 7 (2) : Electrical Installation Systems

University

10 Qs

Electrical Faults and Overcurrent Quiz

Electrical Faults and Overcurrent Quiz

KG - University

10 Qs

Understanding Electrical Systems and Components

Understanding Electrical Systems and Components

KG - University

10 Qs

Understanding Voltage and Current

Understanding Voltage and Current

1st Grade

10 Qs

13 Sine wave quantities (A)

13 Sine wave quantities (A)

Assessment

Quiz

Construction

Vocational training

Medium

Created by

Paul Ward

Used 2+ times

FREE Resource

8 questions

Show all answers

1.

FILL IN THE BLANK QUESTION

30 sec • 1 pt

1. A sine wave has a peak voltage of 100V; calculate the RMS value. (1dp)

2.

FILL IN THE BLANK QUESTION

30 sec • 1 pt

2. A sine wave has a peak voltage of 100V; calculate the average value. (1dp)

Answer explanation

Average Voltage = Peak Voltage × 0.636

Average Voltage= 100 × 0.636= 63.6 Volts

3.

FILL IN THE BLANK QUESTION

30 sec • 1 pt

3.A sine wave has a peak voltage of 565.7V; calculate the RMS value.

(Nearest whole number)

4.

FILL IN THE BLANK QUESTION

30 sec • 1 pt

4.A sine wave has a peak voltage of 565.7V; calculate the average value.

(Nearest whole number)

Answer explanation

Average Voltage = Peak Voltage × 0.636

Average Voltage= 565.7 × 0.636= 359.79 Volts

∴ 360 volts to the nearest whole number

5.

FILL IN THE BLANK QUESTION

30 sec • 1 pt

5. A sine wave has a peak voltage of 90V; calculate the RMS value. (2dp)

6.

FILL IN THE BLANK QUESTION

30 sec • 1 pt

6.A sine wave has a peak voltage of 90V; calculate the average value.

(2dp)

Answer explanation

Average Voltage = Peak Voltage × 0.636

Average Voltage= 90 × 0.636= 57.24 Volts

∴ The answer is 57.24 volts

7.

FILL IN THE BLANK QUESTION

30 sec • 1 pt

7.A sine wave has an RMS voltage of 40V; calculate the peak value. (1dp)

Answer explanation

Peak Voltage =RMS Voltage/0.707

or

Peak Voltage=RMS Voltage × √2

40∕0.707 = 56.6 Volts (1dp)

40 × √2 = 56.6 Volts (1dp)

8.

FILL IN THE BLANK QUESTION

30 sec • 1 pt

8. A sine wave has an RMS voltage of 200V; calculate the peak value.

(Nearest whole number)

Answer explanation

Peak Voltage =RMS Voltage/0.707

or

Peak Voltage=RMS Voltage × √2

200∕0.707 = 283 Volts (Nearest whole number)

200 × √2 = 283 Volts (Nearest whole number)