Hardy Weinberg Equilibrium

A rather large population of foxes has 555 individuals with tan fur and 390 individuals with red fur. Assume that red is recessive.

Now that you have q, what should you solve for next?

• p

• q

• q²

• p²

Tags

NGSS.HS-LS3-3

p + q = 1. If p represents the dominant allele frequency, what would q represent?

• the homozygous dominant genotype frequency

• the recessive allele frequency

• the total amount of alleles in the population

• a measure of fitness in the population

p + q always equals 1. Which answer choice best explains this?

• individual could have a dominant or a recessive allele.

• The population is in Hardy-Weinberg equilibrium. The 1 indicates that the population has not evolved.

• In terms of frequency, 1 is the highest possible number you can have.

• In terms of frequency, 1 is the same as 100%. All alleles in a population added up give you 100% of the alleles.

Tags

NGSS.HS-LS4-3

The gene pool for a population of 10 individuals contains 4 recessive alleles and 16 dominant alleles (20 alleles total). What is the value for p (dominant allele frequency)?

Tags

NGSS.HS-LS4-3

p² + 2pq + q² = 1 Which numeric value should be plugged in for 2pq?

Tags

NGSS.HS-LS4-3

0.49 + 2pq + 0.09 =1 Find the value for 2pq.

A rather large population of foxes has 555 individuals with tan fur and 390 individuals with red fur. Assume that red is recessive.

What should you try to start with?

• p

• q

• q²

• p²

Tags

NGSS.HS-LS4-3

A rather large population of foxes has 555 individuals with tan fur and 390 individuals with red fur. Assume that red is recessive. Calculate the following: 

1. The frequencies of each allele. 

2. The frequencies of each genotype.

3. How many foxes are of the heterozygous genotype?

Answer explanation

Tags

NGSS.HS-LS3-2

NGSS.HS-LS3-3

If the frequency of recessive allele is 0.2, what is the frequency of the homozygous recessive individuals?

• 0.04

• 0.16

• 0.4

• 0.8

Answer explanation

The frequency of homozygous recessive individuals is 0.04, which is calculated by squaring the frequency of the recessive allele (0.2 x 0.2 = 0.04).

Tags

NGSS.HS-LS4-3

The allele frequency of p=.20 What is the frequency of the heterozygous genotype?

• .80

• .04

• .32

• .64

Answer explanation

This is a 2 step qestion.

1. Find q by plugging in p to the equation p + q = 1. You should get q = 0.8

2. Plug in p and q to 2pq to find the heterozygous frequency. 2(0.2)(0.8) = 0.32

Tags

NGSS.HS-LS4-3