Chemical Calculations

How many moles of H₂SO₄ in 70g

H = 1

O = 16

S = 32

30cm³ of NaOH is neutralised by 12.3cm³ of 0.2mol/l HCl. What is the concentration of the NaOH.

• 82 mol/l

• 0.82 mol/l

• 0.49 mol/l

• 0.082 mol/l

How many moles of NaOH will neutralise 18.3cm³ of 1.0 mol / dm³ HCl solution?

• 6.02 x 10²³ mol

• 1.83 x 10⁴ mol

• 0.0183 mol

• 18.3 mol

Tags

moles = conc x vol

How many moles of H₂SO₄ will neutralise 14.2 cm³ of 0.01 mol/dm³ NaOH?

• 1.42 x 10⁴ mol

• 7.1 x 10^-5 mol

• 1.42 x 10^-4 mol

• 7.1 x 10⁵ mol

Answer explanation

Each mole of H₂SO₄ neutralises 2 moles of NaOH

Tags

moles = conc x vol

reacting ratio

What volume of 0.01 mol/dm³ HCl solution will neutralise 50cm³ of 0.01 mol/dm³ NaOH solution?

• 0.25cm³

• 25cm³

• 50cm³

• 100cm³

Tags

moles = conc x vol

vol = moles / conc

H₂SO₄ + 2NaOH --> Na₂SO₄ + 2H₂O

To 2 dp, what volume of 2.0 mol/dm³ H₂SO₄ solution will neutralise

36.20cm³ of 2.0 mol/dm³ NaOH solution?

• 36.20cm³

• 18.10cm³

• 0.04cm³

• 0.02cm³

Answer explanation

Each mole of H₂SO₄ neutralises 2 moles of NaOH

Tags

moles = conc x vol

vol = moles / conc

reacting ratio

What is the reading on this burette?

• 24.0cm³

• 25.8cm³

• 24.2cm³

• 23.9cm³

Which of these titres are concordant?

• 12.7cm³

• 12.3cm³

• 12.4cm³

• 12.0cm³

A(n) ___________ is a procedure in which a solution of known concentration is used to determine the concentration of an unknown solution.

• experiment

• titration

• chemistry

• reaction

What is the concentration of the NaOH solution, if 20.0cm³ of it is neutralised by 25.00cm³ of 0.1 mol/dm³ H₂SO₄ solution?

• 0.75 mol/dm³

• 1.0 mol/dm³

• 1.25 mol/dm³

• 0.25 mol/dm³

Answer explanation

Each mole of H₂SO₄ reacts with 2 moles of NaOH

Tags

conc = moles / vol

reacting ratio

moles = conc x vol

acids as monoprotic/diprotic/triprotic