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Thermo Review

Authored by Lisa Thompson

Science

11th Grade

NGSS covered

Thermo Review
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15 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 3 pts

Media Image

What is the total compressed volume in an ideal Otto Cycle, which starts at 27 C and 90 kPa, has a compression ratio of 7, and 0.004181 kg of air? Props: Cp=1.005 [kJ/kg K], Cv=0.718 [kJ/kg K], K=1.4, R= 0.287 [kJ/kg K]

0.9567 m^3

0.1366 m^3

0.0005714 m^3

0.003999 m^3

Answer explanation

Use the ideal gas law to calculate the initial specific volume, the compression ratio to find the final specific volume, and then multiply the specific volume by mass to get total volume

Tags

NGSS.HS-PS3-4

NGSS.HS-PS3-2

2.

MULTIPLE CHOICE QUESTION

1 min • 3 pts

Media Image

How much work is done during the power stroke of an ideal Otto Cycle with a maximum temperature of 1127 C, compression ratio of 7, and 0.004181 kg of air? Props: Cp=1.005 [kJ/kg K], Cv=0.718 [kJ/kg K], K=1.4, R= 0.287 [kJ/kg K]

1.831 kJ

2.273 kJ

2.241 kJ

1.029 kJ

Answer explanation

Use an isentropic process relationship to find the gas temperature at the end of the power stroke, then use the temperature difference, Cv, and the mass to calculate the work done.

Tags

NGSS.HS-PS3-1

3.

MULTIPLE CHOICE QUESTION

1 min • 3 pts

Media Image

An ideal Otto cycle running with air rejects 327 kJ/kg of waste heat each cycle. What is the pressure of the gas before heat rejection if at the end of the heat rejection process the gas is 27 C and 95 kPa. Props: Cp=1.005 [kJ/kg K], Cv=0.718 [kJ/kg K], K=1.4, R= 0.287 [kJ/kg K]

239 kPa

755 kPa

534 kPa

4392 kPa

Answer explanation

Because this is a constant volume process,

Pv/T = R

allows you to relate both states (through R) where v cancels on both sides (constant volume process) creating P2/T2 = P1/T1. You have enough information to solve for P1 using this information if you also calculate T1.

Tags

NGSS.HS-PS3-4

NGSS.HS-PS3-1

4.

MULTIPLE CHOICE QUESTION

1 min • 3 pts

Media Image

An ideal Otto cycle running with air starts its cycle at 27 C and 95 kPa. After the compression stroke, the gas state is 416 C and 1745 kPa. What's the compression ratio (r) of this cycle?

1.2

8

7

10

Answer explanation

You can arrange the ideal gas law as,

v = RT/P

giving you enough information to calculate the specific volume at both states. The compression ratio is then r =v1/v2

Tags

NGSS.HS-PS3-4

NGSS.HS-PS3-1

5.

MULTIPLE CHOICE QUESTION

1 min • 3 pts

Media Image

How much mass is in an ideal Otto Cycle which starts at 27 C and 90 kPa, has a compression ratio of 7, a maximum cycle temperature of 1127 C, and 1.029 kJ of total heat rejection per cycle? Props: Cp=1.005 [kJ/kg K], Cv=0.718 [kJ/kg K], K=1.4, R= 0.287 [kJ/kg K]

0.004181 kg

0.04646 kg

0.00283 kg

0.002988 kg

Answer explanation

Use r to get efficiency, use efficiency to calculate Q_in based on Q_out, then use Q=m*Cv*ΔT to calculate mass based on the heat addition to the cycle.

Tags

NGSS.HS-PS3-4

NGSS.HS-PS3-1

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What will increase the efficiency of an Otto Cycle: Increasing the compression ratio or increasing the amount of air in the cycle?

Increase Compression Ratio

Increase Air in Cycle

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Increasing the amount of air in a cycle will not increase the total net work produced by a cycle.

True

False

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