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When you are checking functions to see if they are inverses, what do you have to check?

Select all that apply.

•  $\left(f\circ g\right)\left(x\right)\ =x$  

•  $\left(g\circ f\right)\left(x\right)\ =\ x$  

•  $f\left(x\right)\ =x$  

•  $g\left(x\right)=x$  

Tags

CCSS.HSF-BF.B.4B

If you have the functions

 $f\left(x\right)=\sqrt{x+2}-7$   $g\left(x\right)=\left(x+7\right)^2-2$  
what does  $\left(f\circ g\right)\left(x\right)\$ look like?

•  $\left(f\circ g\right)\left(x\right)=\sqrt{\left(\left(x+7\right)^2-2\right)+2}-7$  

•  $\left(f\circ g\right)\left(x\right)=\left(\left(\sqrt{x+2}-7\right)+7\right)^2-2$  

•  $\left(f\circ g\right)\left(x\right)=\sqrt{x+2}^2-7$  

•  $\left(f\circ g\right)\left(x\right)=\sqrt{x+7}^2-2$  

Tags

CCSS.HSF-BF.A.1C

If you have the functions

 $f\left(x\right)=\sqrt{x+2}-7$   $g\left(x\right)=\left(x+7\right)^2-2$  
what does  $\left(g\circ f\right)\left(x\right)\$ look like?

•  $\left(g\circ f\right)\left(x\right)=\sqrt{\left(\left(x+7\right)^2-2\right)+2}-7$  

•  $\left(g\circ f\right)\left(x\right)=\left(\left(\sqrt{x+2}-7\right)+7\right)^2-2$  

•  $\left(g\circ f\right)\left(x\right)=\sqrt{x+2}^2-7$  

•  $\left(g\circ f\right)\left(x\right)=\sqrt{x+7}^2-2$  

Tags

CCSS.HSF-BF.A.1C

What can you do to help yourself on these problems?

• Take your time.

• Show all your steps.

• Double-check your work.

• All of the above.

Tags

CCSS.8.EE.C.7B

Tags

CCSS.HSF-BF.B.4C

What is the inverse of the points (1,3)(2,4)(6,2)

• (2,6)(3,1)(4,2)
• (-3,-1)(-4,-2)(-2,-6)
• (1,3)(2,4)(6,2)
• (-1,-3)(-2,-4)(-6,-2)

Tags

CCSS.HSF-BF.B.4C

What does it mean to find the inverse of a function?

• the x's and y's are switched
• the x's and y's are divided by 2
• the x's and y's are made negative
• the x's and y's are the same

Tags

CCSS.HSF-BF.B.4A

If the equation of f(x) goes through (1, 4) and (4, 6), what points does f^-1(x) go through?

• (1, 4) and (4, 6)
• (-4, -1) and (-6, -4)
• (-1, -4) and (-4, -6)
• (4, 1) and (6, 4)

Tags

CCSS.HSF-BF.B.4C

The inverse has been reflected over which line?

• y = x
• y =1
• y = 0
• y = x + 1

Tags

CCSS.HSF-BF.B.4B

When finding the inverse of a relation, 
1st you replace f(x) with y
2nd switch the x's and y's
What do you do next?

• solve for y
• replace y with f^-1(x)
• solve for x
• find the greatest common factor

Tags

CCSS.HSF-BF.B.4A