C Programming Lab Quiz 1

Identify the option that does not represent a logical operator:

• && 

• || 

• ! 

• | 

Which of the following is a valid C expression for declaring an integer variable?

• int my_num = 100,000;

• int my_num = 100000;

• int my num = 1000;

• int $my_num = 10000;

Which for loop has range of similar indexes of ‘i’ used in for (i = 0;i < n; i++)?

• for (i = n; i>0; i--)

• for (i = n; i >= 0; i--)

• for (i = n-1; i>0; i--)

• for (i = n-1; i>-1; i--)

What will be the output of the following C code?

#include <stdio.h>

void main()

{

double k = 0;

for (k = 0.0; k < 3.0; k++)

printf("Hello");

}

• Run time error

• Hello is printed thrice

• Hello is printed twice

• Hello is printed infinitely

#include<stdio.h>

void main() {
int num = 0;
do {
- - num;
printf(“%d”, num);
num ++;
}
while(num >= 0);
}

• Infinite loop printing 0
• Prints numbers from 0 to 10
• Prints -1 and exits immediately
• Infinite loop printing -1

What is the value of ‘grade’ after the switch statement is executed?

#include<stdio.h>

int marks = 80;
switch(marks) {
  case 60:
    grade = ‘C’;
    break;
  case 70:
    grade = ‘B’;
    break;
  case 80:
    grade = ‘A’;
    break;
  default:
    grade = ‘E’;

• C
• B
• D
• A

If switch feature is used, then

• Default case must be present

• Default case, if used, should be the last case

• Default case, if used, can be placed anywhere

• None of the above

In the context of "break" and "continue" statements in C, pick the best statement.

• "break" and "continue" can be used in "for", "while", "do-while" loop body and "switch" body

• "break" and "continue" can be used in "for", "while" and "do-while" loop body. But only "break" can be used in "switch" body

• "break" and "continue" can be used in "for", "while" and "do-while" loop body. Besides, "continue" and "break" can be used in "switch" and "if-else" body

• "break" can be used in "for", "while" and "do-while" loop body

#include <stdio.h>

void main()

{

int i = 0;

if (i == 0)

{

printf("Hello");

break;

}

}

• The variable 'i' will be incremented to 1.
• Code will compile successfully.
• The program will print 'Hello' and exit.
• Code will not compile due to misuse of 'break'.

What will be the output of the following C code?

#include <stdio.h>

int main()

{

int i = 0;

do

{

i++;

if (i == 2)

continue;

printf("In while loop ");

} while (i < 2);

printf("%d\n", i);

}

• In while loop 2

• In while loop in while loop 3

• In while loop 3

• Infinite loop