(2x³ - 5x² + 3x + 7) ÷ (x - 2)

• 2x³ - x² + x + 9
• 2x² - x + 1
• 2x² - x + 1 + 9/x-2
• 2x² - 9x - 15 - 23/x-2

Tags

CCSS.HSA.APR.D.6

(3x³ - 2x² - 7x + 6) ÷ (x + 1)

• 3x³ - 5x² - 2x + 8
• 3x² + x - 6
• 3x² - 5x - 2 + 8/x+1
• 3x³ + x² - 6x

Tags

CCSS.HSA.APR.D.6

What should be the order of the polynomial coefficients if
(3x - 4x³ + 6x⁴ + 1) / (x + 3)

• 3   0   -4   6   1
• 6   -4   3   1   0
• 6   -4   0   3   1
• -6   4   0   -3   -1

Tags

CCSS.HSA.APR.D.6

If you were dividing x⁶ + 4x³ + 2, how many 0's would you need when setting up the top row of your synthetic division?

• 0
• 2
• 4
• 6

Tags

CCSS.HSA.APR.D.6

For synthetic division, what would be the number in the left hand box?

• 0
• 1
• 2
• 3

Tags

CCSS.HSA.APR.D.6

(3x³ + 5x - 1) ÷ (x + 1)

• 3x³ - 3x² + 8x - 9
• 3x² - 3x + 8 - 9/x+1
• 3x² + 3x + 8 + 7/x+1
• 3x³ + 3x² + 8x + 7

Tags

CCSS.HSA.APR.D.6

(2x³ - 5x - 7) ÷ (x - 2)

• 2x³ - 4x² + 3x - 13
• 2x³ + 4x² +3x - 1
• 2x² - 4x + 3 - 13/x-2
• 2x² + 4x + 3 - 1/x-2

Tags

CCSS.HSA.APR.D.6

Use synthetic division:
(2x³ - 5x - 7) ÷ (x - 2)

• 2x³ - 4x² + 3x - 13
• 2x³ + 4x² +3x - 1
• 2x² - 4x + 3 - 13/x-2
• 2x² + 4x + 3 - 1/x-2

Tags

CCSS.HSA.APR.D.6

Cam divided (x⁴ + 3x² - 4x - 2) by factor of (x-2) using synthetic division. His work is shown above. Which best describes his mistake?

• Cam wrote the remainder incorrectly.

• Cam did not use a zero place holder for the x³ term.

• Cam added instead of subtracting the rows.

• Cam should have used -2 as his division since the factor was x-2.

Tags

CCSS.HSA.APR.D.6

If you are missing an exponent in your polynomial you must put a zero as a coefficient place holder for that exponent

• True
• False