Determining Multiples of 2, 3, and 6 Using Divisibility Rules

Determining Multiples of 2, 3, and 6 Using Divisibility Rules

Assessment

Interactive Video

Mathematics, Social Studies

1st - 6th Grade

Hard

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Quizizz Content

FREE Resource

This video tutorial explains how to determine if a number is a multiple of 2, 3, or 6 using divisibility rules. It covers the concept of divisibility, showing that a number is divisible if it can be evenly divided by another number. The tutorial provides specific rules for divisibility by 2, 3, and 6, using examples to illustrate each rule. For 2, a number must be even; for 3, the sum of its digits must be a multiple of 3; and for 6, it must meet the criteria for both 2 and 3. The video concludes by applying these rules to determine if 84 is a multiple of 6.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does it mean for a number to be divisible by another number?

It can be divided into decimals.

It can be divided into fractions.

It can be divided with a remainder.

It can be divided evenly without a remainder.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following numbers is divisible by 2?

15

47

23

36

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If a number ends in 0, what can be said about its divisibility?

It is divisible by 7.

It is divisible by 5.

It is divisible by 3.

It is divisible by 2.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the divisibility rule for 3?

The number ends in 0, 2, 4, 6, or 8.

The sum of the digits is a multiple of 3.

The number is a prime number.

The number is an odd number.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following numbers is not divisible by 3?

72

23

33

96

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What must be true for a number to be divisible by 6?

It must be a prime number.

It must be divisible by both 2 and 3.

It must be divisible by 3 only.

It must be divisible by 2 only.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Is the number 72 divisible by 6?

Yes, because it is divisible by both 2 and 3.

No, because it is not divisible by 2.

No, because it is not divisible by 3.

Yes, because it is a prime number.