KISI ATS KIMIA KLS XI Sem 2

KISI ATS KIMIA KLS XI Sem 2

11th Grade

40 Qs

quiz-placeholder

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KISI ATS KIMIA KLS XI Sem 2

KISI ATS KIMIA KLS XI Sem 2

Assessment

Quiz

Chemistry

11th Grade

Hard

NGSS
HS-PS1-4, HS-PS3-1, HS-PS3-4

Standards-aligned

Created by

ESRA GULTOM

Used 3+ times

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40 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Ciri-ciri reaksi eksoterm adalah … .

lingkungan menyerap kalor dari sistem

sistem menyerap kalor dari lingkungan

sistem dan lingkungan memiliki kalor sama

kalor sistem dan lingkungan jika dijumlahkan sama dengan nol

pada akhir reaksi, kalor lingkungan selalu lebih kecil dari kalor sistem

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Sebanyak 2 mol gas hidrogen jika direaksikan dengan 1 mol gas oksigen akan terbentuk uap air yang membutuhkan kalor sebesar 484 kJ. Persamaan termokimianya adalah … .

H2(g) + ½ O2(g) --> H2O(g) ΔH = 484 kJ

2 H2(g) + O2(g) --> 2 H2O(g) ΔH = 484 kJ

2 H2(g) + O2(g) --> 2 H2O(g) ΔH = –484 kJ

2 H2O(g) --> 2 H2(g) + O2(g) ΔH = –484 kJ

H2O(g) --> H2(g) + ½ O2(g) ΔH = 484 kJ

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Terjadinya reaksi endoterm ditunjakkan pada gambar nomor…

1 dan 3

2 dan 4

1 dan 4

1 dan 2

3 dan 4

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Perhatikan persamaan termokimia berikut :

2CuCl(s) → 2Cu(s) + Cl2(g) ΔH = +274,4 kJ

2CuCl(s) + Cl2(g) → 2CuCl2(s) ΔH = -165,8 kJ

ΔH untuk reaksi :

Cu(s) + Cl2(g) → CuCl2(s)

yaitu,....

43 kJ/mol

86 kJ/mol

484 kJ/mol

570 kJ/mol

1054 kJ/mol

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Data energi ikatan rata rata :

C=C = 609 kJ/mol

C-Cl = 326 kJ/mol

C-H = 412 kJ/mol

C-C = 345 kJ/mol

H-Cl = 426 kJ/mol

Besarnya entalpi reaksi

CH2=CH2 + HCl → CH3CH2Cl

adalah,......

-312 kJ/mol

-48 kJ/mol

48 kJ/mol

100 kJ/mol

312 kJ/mol

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

+ 712

+492

-492

-712

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Berikut ini yang merupakan reaksi pembentukan standar adalah ....

Ca(s) + O(g) + H(g) ------> Ca(OH)2 (s) ΔH = -a kal

Ca2+(s) + O2 (g) + H2(g) ------> Ca(OH)2 (s) ΔH = -a kal

Ca(s) + O2 (g) + H2(g) ------> Ca(OH)2 (s) ΔH = -a kal

Ca(s) + 2O2(g) + 2H(g) ------> Ca(OH)2 (s) ΔH = -a kal

2Ca(s) + O2(g) + H2(g) ------> 2Ca(OH)2 (s) ΔH = -a kal

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