Centripetal Acceleration Derivation

Centripetal Acceleration Derivation

Assessment

Interactive Video

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Quizizz Content

Physics, Science

11th Grade - University

Hard

The video tutorial explains centripetal acceleration and force, starting with Newton's second law. It derives the equation for centripetal acceleration using average linear acceleration and explores the roles of angular and tangential velocity. Vector diagrams and isosceles triangles are used to illustrate the concepts, leading to the final derivation of the centripetal acceleration equation.

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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between centripetal force and centripetal acceleration according to Newton's second law?

Centripetal force is the sum of centripetal acceleration and mass.

Centripetal force is the product of mass and centripetal acceleration.

Centripetal force is the difference between mass and centripetal acceleration.

Centripetal force is the quotient of centripetal acceleration and mass.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is centripetal acceleration considered a linear acceleration?

Because it acts in a straight line.

Because it is the result of a change in angular velocity.

Because it is the linear acceleration of an object moving in a circular path.

Because it is always constant.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between tangential velocity and angular velocity?

Tangential velocity is the quotient of angular velocity and radius.

Tangential velocity is the difference between angular velocity and radius.

Tangential velocity is the product of radius and angular velocity.

Tangential velocity is the sum of angular velocity and radius.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why does the tangential velocity of an object moving in a circle not remain constant?

Because it stops moving.

Because its magnitude changes.

Because its direction changes.

Because both its magnitude and direction change.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the isosceles triangle in the derivation of centripetal acceleration?

It proves that the object is not moving.

It helps in understanding the relationship between change in velocity and position.

It demonstrates that the change in position is zero.

It shows that the radius is always changing.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the direction of centripetal acceleration determined?

It is always perpendicular to the radius.

It is always parallel to the tangential velocity.

It is always directed inward toward the center of the circle.

It is always directed outward from the center of the circle.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the similarity of triangles in the derivation indicate?

The change in velocity is less than the change in position.

The change in velocity is greater than the change in position.

The change in velocity is proportional to the change in position.

The change in velocity is unrelated to the change in position.

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final expression for centripetal acceleration derived in the video?

Centripetal acceleration equals tangential velocity squared over radius.

Centripetal acceleration equals tangential velocity over radius squared.

Centripetal acceleration equals radius squared over tangential velocity.

Centripetal acceleration equals radius over tangential velocity squared.

9.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What remains constant for an object moving at a constant angular velocity?

The magnitude of tangential velocity.

The angular acceleration.

The direction of tangential velocity.

The centripetal acceleration.

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What causes centripetal acceleration in an object moving in a circle?

The change in radius of the circle.

The change in direction of tangential velocity.

The change in magnitude of tangential velocity.

The change in mass of the object.

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