Integrated Rate Equations

Integrated Rate Equations

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

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The video tutorial explains zero and first order reactions, their rate equations, and the concept of half-life. It covers the decomposition of ammonia and the hydrogenation of ethene, illustrating how reaction rates are affected by reactant concentration. The tutorial also introduces pseudo first order reactions, using the hydrolysis of methyl acetate as an example.

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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the characteristic of a zero order reaction regarding the concentration of the reactant?

The rate increases with concentration.

The rate decreases with concentration.

The rate is independent of concentration.

The rate fluctuates with concentration.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the decomposition of ammonia on a platinum surface, what role does platinum play?

Inhibitor

Catalyst

Product

Reactant

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which graph represents a zero order reaction?

A curve with a decreasing slope

A straight line with a positive slope

A straight line with a negative slope

A curve with an increasing slope

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In a first order reaction, what happens to the rate as the concentration of the reactant decreases?

The rate becomes zero.

The rate decreases.

The rate remains constant.

The rate increases.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between the half-life and concentration in a first order reaction?

Directly proportional

Inversely proportional

Independent

Exponentially related

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For a zero order reaction, how does the half-life change as the reaction progresses?

It remains constant.

It decreases.

It increases.

It becomes zero.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the half-life equation for a first order reaction?

t1/2 = k/0.693

t1/2 = 0.693/k

t1/2 = R0/2k

t1/2 = 2.303/k

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