Derivative product rule with inverse tangent

Derivative product rule with inverse tangent

Assessment

Interactive Video

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Mathematics

11th Grade - University

Hard

The video tutorial explains the product rule in calculus, focusing on its application to functions involving the arctan and square root. The instructor guides students through the process of applying the product rule, simplifying expressions, and understanding the importance of presenting answers in a simplified form for different types of assessments. The tutorial emphasizes the need to recognize and simplify expressions for multiple-choice tests and provides correct answers for practice problems.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in applying the product rule to a function involving arctan?

Multiply the entire function by its derivative

Identify the inverse function and differentiate it

Multiply by the square root of the function

Apply the chain rule first

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When applying the product rule, what is the derivative of the square root of x?

x^2

1/2 * x^(-1/2)

2x

x^(1/2)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can you express x^(1/2) in terms of fractions?

x^(1/3)

1/x

x^2

x^(1/2)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a key reason for simplifying expressions in calculus problems?

To avoid using the product rule

To prepare for multiple-choice tests

To ensure they fit on a single line

To make them look more complex

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens when you divide fractions in the context of simplifying expressions?

You divide the numerators

You multiply the fractions

You add the exponents

You subtract the exponents