S = 3F - 24 Solve for F

f = 1 3 s + 8 f=\frac{1}{3}s+8 f = 3 1 s + 8

f = 1 3 s − 8 f=\frac{1}{3}s-8 f = 3 1 s − 8

Solve the following equation for the indicated variable: t = 1 4 v , f o r v t=\frac{1}{4}v\ \ ,\ \ for\ v t = 4 1 v , f o r v

v = t + 1 4 v=t+\frac{1}{4} v = t + 4 1

Solve the following equation for the indicated variable: a = 3 b − 9 , f o r b a=3b-9\ \ ,\ \ for\ b a = 3 b − 9 , f o r b

b = 1 3 a + 3 b=\frac{1}{3}a+3 b = 3 1 a + 3

b = 1 3 a − 3 b=\frac{1}{3}a-3 b = 3 1 a − 3

P = 144 p y , s o l v e f o r p P=\frac{144p}{y},\ solve\ for\ p P = y 1 4 4 p , s o l v e f o r p

P y 144 = p \frac{Py}{144}=p 1 4 4 P y = p

144 P y = p \frac{144P}{y}=p y 1 4 4 P = p

P 144 y = p \frac{P}{144y}=p 1 4 4 y P = p

144 P y = p \frac{144}{Py}=p P y 1 4 4 = p

Solve for a: 12 a m = b 12am=b 1 2 a m = b

a = b 12 m a=\frac{b}{12m} a = 1 2 m b

a = 12 m b a=\frac{12m}{b} a = b 1 2 m

a = 12 − m b a=12-mb a = 1 2 − m b

LITERAL EQUATION

Quiz

•

Mathematics

•

9th - 12th Grade

•

Practice Problem

•

Hard

•

CCSS

HSA.CED.A.4, HSA.REI.B.3, HSA.SSE.B.3

Standards-aligned

Daniel Gyanko

FREE Resource

50 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 12 pts

Solve -2 = 4r + s for s.

s = -2 + 4r

s = 2 - 4r

s = -2 - 4r

s = 2 + 4r

2.

MULTIPLE CHOICE QUESTION

5 mins • 12 pts

Solve for x:

x = yb - v

x = by - v

x = by + v

3.

MULTIPLE CHOICE QUESTION

5 mins • 12 pts

Solve for n:
2m - n = 8

n = 2m - 8

n = -2m - 8

n = 2m + 8

n = -2m + 8

4.

MULTIPLE CHOICE QUESTION

30 sec • 12 pts

Solve for x: u = 2x - 2

5.

MULTIPLE CHOICE QUESTION

30 sec • 12 pts

Solve for a: 12am = 4

a = 4 -12m

6.

MULTIPLE CHOICE QUESTION

30 sec • 12 pts

a = ukb

a = uk + b

7.

MULTIPLE CHOICE QUESTION

30 sec • 12 pts

k = 24-x

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LITERAL EQUATION

50 questions

Solve -2 = 4r + s for s.

Solve for x:

Solve for n:2m - n = 8

Solve for x: u = 2x - 2

Solve for a: 12am = 4

2. Given 15x + 1 = y, solve for x.

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Solve for n:
2m - n = 8