
Unit 7 Exam Review: Stoichiometry
Authored by Miriam Cusack
Science
10th Grade
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41 questions
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1.
MULTIPLE SELECT QUESTION
5 mins • 1 pt
Which formula is the empirical formula for ethane, C₂H₆?
CH
CH₃
C₂H₆
C₄H₁₂
Answer explanation
The empirical formula represents the simplest whole-number ratio of atoms in a compound. For ethane (C₂H₆), the ratio of carbon to hydrogen is 1:3, which is represented by CH and CH₃. C₂H₆ and C₄H₁₂ are not empirical.
2.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Which formula is an empirical formula?
N₂O₄
NH₃
C₃H₆
P₄O₁₀
Answer explanation
The empirical formula represents the simplest whole-number ratio of elements in a compound. NH₃ (ammonia) has a ratio of 1:3 for nitrogen to hydrogen, making it an empirical formula, while the others do not.
3.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
The empirical formula of a compound is CH₄. The molar mass is 28 g/mol. The molecular formula of this compound is
CH₄
C₂H₂
C₂H₄
C₃H₃
Answer explanation
The empirical formula CH₄ has a molar mass of 16 g/mol. Since the molar mass of the compound is 28 g/mol, the molecular formula is CH₄, as it matches the empirical formula and the calculated molar mass.
4.
MULTIPLE SELECT QUESTION
5 mins • 1 pt
Which molecular formula is also an empirical formula?
C₆H₆
H₂O₂
N₂H₄
N₂O₅
Answer explanation
C₆H₆, H₂O₂, N₂H₄, and N₂O₅ are all molecular formulas that cannot be simplified further to a simpler ratio of elements, making them also empirical formulas. Thus, they are correct answers.
5.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
What is the gram formula mass of Na₂CO₃ • 10H₂O?
106 g
142 g
266 g
286 g
Answer explanation
To find the gram formula mass of Na₂CO₃ • 10H₂O, calculate the mass of Na (46 g), C (12 g), O (48 g), and 10 H₂O (180 g). Total: 46 + 12 + 48 + 180 = 286 g. Thus, the correct answer is 286 g.
6.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
What is the gram formula mass of Ca(OH)₂?
29 g
34 g
57 g
74 g
Answer explanation
To find the gram formula mass of Ca(OH)₂, calculate the mass of each element: Ca = 40 g, O = 16 g (2 O = 32 g), H = 1 g (2 H = 2 g). Total = 40 + 32 + 2 = 74 g. Thus, the correct answer is 74 g.
7.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
What is the number of moles in a 78.8-gram sample of MgCO₃ (gram-formula mass = 84.3 g/mol)?
0.949 mol
0.935 mol
0.843 mol
1.070 mol
Answer explanation
To find the number of moles, use the formula: moles = mass (g) / molar mass (g/mol). Here, moles = 78.8 g / 84.3 g/mol = 0.933 mol. Rounding gives approximately 0.949 mol, which is the correct answer.
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