Solving Quadratic Equations by Factoring and Square Roots

Solving Quadratic Equations by Factoring and Square Roots

9th Grade

10 Qs

quiz-placeholder

Similar activities

RACIOCÍNIO LÓGICO - Equ. e Sist. de Equações - Lógica

RACIOCÍNIO LÓGICO - Equ. e Sist. de Equações - Lógica

9th Grade

14 Qs

LOGARITHMS

LOGARITHMS

9th - 12th Grade

12 Qs

RPA Changing subject 2

RPA Changing subject 2

7th - 9th Grade

10 Qs

REMOVAL OF BRACKETS INTRODUCTION

REMOVAL OF BRACKETS INTRODUCTION

8th - 10th Grade

10 Qs

9N01 Exponents

9N01 Exponents

9th Grade

10 Qs

10.1 Factors review

10.1 Factors review

7th - 10th Grade

15 Qs

Ayo Mengingat Kembali

Ayo Mengingat Kembali

KG - University

10 Qs

Robotica 2018

Robotica 2018

5th - 9th Grade

11 Qs

Solving Quadratic Equations by Factoring and Square Roots

Solving Quadratic Equations by Factoring and Square Roots

Assessment

Quiz

Mathematics

9th Grade

Hard

CCSS
HSA.REI.B.4, HSA.REI.A.1, HSA.APR.B.3

Standards-aligned

Created by

Tiffanie Flores

FREE Resource

AI

Enhance your content in a minute

Add similar questions
Adjust reading levels
Convert to real-world scenario
Translate activity
More...

10 questions

Show all answers

1.

MATCH QUESTION

30 sec • 4 pts

Match each equation with its solution using the Zero Product Property:

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.4

2.

DRAG AND DROP QUESTION

2 mins • 2 pts

Solve by factoring: x2 - 9x = -20
The solutions are x = (a)   and x = (b)   .

x = -4 and x = -5
x = 20 and x = -9
x = 4 and x = 5
x = -4 and x = 5

3.

MATCH QUESTION

2 mins • 4 pts

Match the following equations with their solutions.

x2 + 3x - 18 = 0

x = 3 and x = -6

x2 + 7x - 18 = 0

x = -9 and x = 2

x2 - 3x - 18 = 0

x = 9 and x = -2

x2 - 7x - 18 = 0

x = -3 and x = 6

4.

MULTIPLE SELECT QUESTION

45 sec • 1 pt

3

0

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

5.

MATCH QUESTION

30 sec • 4 pts

Match the following equations with their solutions. (HINT: c is missing)

6.

DROPDOWN QUESTION

15 mins • 6 pts

If the discriminant is positive, d ​ (a)   0, then there are ​ (b)   real solutions.

If the discriminant is zero, d ​ (c)   0, then there is ​ (d)   real solution.

If the discriminant is negative, d ​ (e)   0, then there are no real solutions.

>
2
=
1
<
0
3

7.

CATEGORIZE QUESTION

5 mins • 3 pts

Organize these options into the right categories

Groups:

(a) No Real Solutions

,

(b) One Real Solution

,

(c) Two Real Solutions

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?