Understanding C++ Operators and Casting

What is the purpose of the scope resolution operator (::) in C++?

• To perform arithmetic operations on variables.

• To specify the context of a name and access global or class members.

• To define a new data type in C++.

• To create a pointer to a class member.

How do you use the member dereferencing operator (->) in C++?

• Use the -> operator to access members of a class or structure via a pointer, e.g., pointer->member.

• Use the -> operator to create a new class instance.

• Use the -> operator to declare a pointer variable.

• Use the -> operator to perform arithmetic operations on pointers.

What is the difference between implicit and explicit type casting?

• Explicit type casting is done by the compiler; implicit type casting is done by the programmer.

• Implicit type casting is automatic; explicit type casting is manual.

• Implicit type casting is slower than explicit type casting.

• Implicit type casting requires user intervention; explicit type casting does not.

Provide an example of implicit type casting in C++.

• float f = 10; // Here, the integer 10 is implicitly cast to a float.

• char c = 65; // Here, the integer 65 is implicitly cast to a char.

• int i = 5.0; // Here, the float 5.0 is implicitly cast to an integer.

• double d = 10.5; // Here, the float 10.5 is implicitly cast to a double.

What is the syntax for explicit type casting in C++?

• type_cast(expression)

• static_cast(expression), dynamic_cast(expression), const_cast(expression), reinterpret_cast(expression)

• cast_type(expression)

• convert(expression)

Explain how the scope resolution operator can be used with classes.

• The scope resolution operator allows for variable declaration within a class.

• The scope resolution operator is used to create new classes.

• The scope resolution operator (::) is used to define and implement class member functions outside the class definition.

• The scope resolution operator is used to access global variables only.

What happens if you try to access a member of a class without using the member dereferencing operator?

• You will successfully access the member without any issues.

• The program will automatically use the member dereferencing operator for you.

• You will receive a warning but the member will still be accessed.

• You will encounter an error indicating that the member cannot be accessed.

Can you give an example of a situation where explicit type casting is necessary?

• Casting an integer to a character type.

• Assigning a double to a string variable.

• Using a string as a boolean value.

• Explicit type casting is necessary when using a float as an array index.

What is the result of using the scope resolution operator on a global variable?

• It accesses the global variable, avoiding any local scope conflicts.

• It creates a new local variable with the same name.

• It deletes the global variable from memory.

• It returns the value of the local variable instead.

How does C++ handle type casting between different data types?

• C++ does not support any form of type casting.

• C++ only allows implicit casting between compatible types.

• C++ uses implicit and explicit casting mechanisms, including static_cast, dynamic_cast, const_cast, and reinterpret_cast.

• C++ uses only dynamic_cast for all type conversions.