Quiz on Type Conversion and Operators Precedence

What is operator precedence and why is it important?

• Operator precedence only applies to arithmetic operations.

• Operator precedence is the set of rules that defines the order in which operators are evaluated in expressions first.

• Operator precedence is the same as operator overloading.

• Operator precedence is irrelevant in programming languages.

List the order of operations for arithmetic operators.

• Parentheses, Exponents, Multiplication/Division, Addition/Subtraction

• Exponents, Parentheses, Addition, Subtraction

• Addition, Subtraction, Multiplication, Division

• Multiplication, Addition, Parentheses, Division

How does associativity affect the evaluation of expressions?

• Associativity affects the order of evaluation for operators of the same precedence.

• Associativity has no impact on the evaluation of expressions.

• Associativity determines the precedence of all operators.

• Associativity only applies to binary operators.

Evaluate the expression: 3 + 4 * 2 - 1. What is the result?

• 8

• 12

• 10

• 6

What is the result of the expression 10 / 2 * 3 + 1 - 5?

• 15

• 11

• 8

• 6

What is the result of the expression 5 + 3 * 2?

• 8

• 6

• 10

• 11

What is implicit type conversion in C?

• Implicit type conversion only occurs in floating-point operations.

• Explicit type conversion in C requires manual intervention by the programmer.

• Implicit type conversion in C is the automatic conversion of data types by the compiler during operations.

• Implicit type conversion is a feature that prevents data loss during type changes.

What is explicit type conversion in C?

• Changing the size of a data type without any operator.

• Explicit type conversion in C is the process of converting one data type to another using a cast operator.

• Implicit type conversion using a cast operator.

• Converting data types automatically without a cast operator.

Find the output of the program:

#include<stdio.h>

void main()

{

int a=4, b=12, c=-3, res;

res = a > b && a < c;

printf("%d\n",res);

res = a==c || a < b;

printf("%d\n",res);

res=b+a*(a*2)-c/a;

printf("%d\n", res);

}

• 0

  1

  44

• 1

  0

  12

• 0

  1

  45

• 1

  0

  44

#include<stdio.h>

int main()

{

int x = 10;

char y = 'a';

float z;

x = x + y;

z = x + 1.0;

printf(""x = %d, z = %.2f"", x, z);

return 0;

}

• x = 107, z = 108.00

• x = 107, z = 108.0000

• x = 107, z = 108.000000

• x = 108, z = 108.000000