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ҰБТ-2 нұсқа

Authored by Пернебай Искахов

Mathematics

11th Grade

ҰБТ-2 нұсқа
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40 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Амалды орында; 25−173⋅25−173\sqrt[3]{\sqrt[]{25}-\sqrt[]{17}}\cdot\sqrt[3]{\sqrt[]{25}-\sqrt[]{17}}

2

5

1

3

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

1963+1413337−141⋅196\frac{196^3+141^3}{337}-141\cdot196 өрнегінің мәнін табыңыз

3025

2125

4156

3404

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Суреттегі BC кесіндісінің ұзындығы

1/3

1/2

√2/2

√3/2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Өрнектің мәнін табыңыз: 2(x+4)+6x, мұндағы x=3

42

32

36

38

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

14x−4y=15 теңдеуіндегі y−ті x арқылы өрнектеңіз

y=−3,75x−3,5

y=−3,5x−3,75

y=3,5x−3,75

y=3,5x+3,75

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Теңдеулер жүйесін шешіңіз: {x+y=10

y=13-2x

(−9;4)

(−5;4)

(3:7)

(8;−2)

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

f(x)=3x5+5x3−2x+3f\left(x\right)=3x^5+5x^3-2x+3 функциясының алғашқы функциясын табыңыз

F(x)=5x66+3x4  4−x2+3x+CF\left(x\right)=\frac{5x^6}{6}+\frac{3x^{4\ \ }}{4}-x^2+3x+C

F(x)=x62+5x4  4−x2+3x+CF\left(x\right)=\frac{x^6}{2}+\frac{5x^{4\ \ }}{4}-x^2+3x+C

F(x)=x62+5x4  4−2x2+3x+CF\left(x\right)=\frac{x^6}{2}+\frac{5x^{4\ \ }}{4}-2x^2+3x+C

F(x)=8x4+15x2−2+CF\left(x\right)=8x^4+15x^2-2+C

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