Final Equilibrium & Reaction Rate Review

Consider the following reaction:
2SO_2(g) + O_2(g) ⇄ 2SO_3(g) +  197 kJ/mol Which of the following will not shift the equilibrium to the right?

• Adding more O₂
• Adding a catalyst
• increasing the pressure
• Lowering the temperature

Identify the incorrect statement about achieving equilibrium.

• achieved when product and reactant concentrations are equal

• achieved when forward and reverse reaction rates are same

• achieved when concentration of reactants is stable/constant

• achieved when concentration ratio of reactants to products becomes stable, thus fixing the equilibrium constant (equilibrium position)

Why is equilibrium called a dynamic state?

• Chemists try to convert as much reactants as possible into products.
• The reactions at equilibrium continue to take place once equilibrium is established.
• The products of a forward reaction are favored, so equilibrium lies to the right.
• All chemical reactions are considered to be reversible under suitable conditions.

At what time (in seconds) is equilibrium established?

• 0 seconds
• 1 second
• 5 seconds
• 10 seconds

B represents

• energy absorbed
• energy released
• activation energy

Tags

NGSS.HS-PS1-4

What type of reaction is this?

• Endothermic
• Exothermic

Tags

NGSS.HS-PS1-4

Which is the correct equilibrium constant expression for the following reaction?

Fe₂O_3(s) + H_2(g) —> Fe_(s) + H₂O_(g)

• K = [H₂O]3 / [H₂]³

• K = [Fe₂O₃] [H₂]³ / [Fe]²[H₂O]³

• K = [Fe]²[H₂O]³ / [Fe_2O₃] [H₂]³

• K= [Fe] [H₂O] / [Fe₂O₃] [H₂]

• K = [H₂] / [H₂O]

Tags

NGSS.HS-PS1-7

Calculate Kc for the reaction HI_(g) —> H_2(g) + I_2(g) given that the concentrations of each species at equilibrium are as follows: [HI] = 0.85 mol/L, [I₂] = 0.60 mol/L, [H₂] = 0.27mol/L.

• 0.19

• 0.22

• 4.5

• 5.25

• 160

A very high value for K indicates that

• reactants are favored.

• products are favored.

• equilibrium is reached slowly.

• equilibrium has been reached

Calculate [H₂O] if K_eq = 1.2,

[CO₂] = 0.846M, and [CH₄]= 0.0713M

4CuO_(s) +CH_4(g) ⇌ CO_2(g)+4Cu_(s) +2H₂O_(g)

• 0.101 M

• 0.318 M

• 0.0102 M

• 3.77 M