Worksheet 27: Sets C and D Molarity

What is the molarity of 1.0 L NaCl solution containing 1.0 mole of the solute?

• 1 M

• 0.5 M

• 2 M

• 1.5 M

What is the concentration of NH4Cl solution containing 2 moles of the solute in 500 ml of the solution?

• 1 M

• 2 M

• 3 M

• 4 M

What is the molarity of a 1500-ml solution containing 3.0 moles of the solute?

• 2.0 M

• 0.5 M

• 1.0 M

• 3.0 M

What is the molar concentration of a solution in which 522 grams of K2SO4 is dissolved in 1.5 liters of the solution?

• 2 M

• 1.5 M

• 3 M

• 4 M

How many moles of solute are there in a 2 L of 1 M solution?

• Moles = Molarity (M) x Volume (L) Moles = 1 x 2 = 2 mol

• Moles = Molarity (M) x Volume (L) Moles = 1 x 1 = 1 mol

• Moles = Molarity (M) x Volume (L) Moles = 2 x 2 = 4 mol

• Moles = Molarity (M) x Volume (L) Moles = 0.5 x 2 = 1 mol

Tags

NGSS.HS-PS1-5

What is the number of moles of LiBr in a 1.5 L of a 2 M LiBr solution?

• Moles = 2 x 1.5 = 3.0 mol

• Moles = 2 x 1.5 = 2.0 mol

• Moles = 2 x 1.5 = 1.5 mol

• Moles = 2 x 1.5 = 4.0 mol

What is the number of moles of NH4Cl in 200 ml of a 0.4 M solution?

• Moles = 0.4 x 0.2 = 0.08 mol

• Moles = 0.4 x 0.2 = 0.04 mol

• Moles = 0.4 x 0.2 = 0.16 mol

• Moles = 0.4 x 0.2 = 0.02 mol

How much volume of a 0.4 M potassium iodide solution contains 0.12 moles of the solute?

• Volume = 0.12 / 0.4 = 0.3 L

• Volume = 0.12 / 0.3 = 0.4 L

• Volume = 0.12 / 0.5 = 0.24 L

• Volume = 0.12 / 0.6 = 0.2 L

What volume of a 3 M H2SO4 solution will contain 0.75 moles of the solute?

• Volume = 0.75 / 3.0 = 0.25 L

• Volume = 0.75 / 3.0 = 0.5 L

• Volume = 0.75 / 3.0 = 0.75 L

• Volume = 0.75 / 3.0 = 1.0 L

How many grams of NH4NO4 are in a 2.3 L sample of a 1.5 molar solution?

• Mass = 1.5 x 2.3 x 96 = 331.2 g

• Mass = 1.5 x 2.3 x 80 = 276 g

• Mass = 1.5 x 2.3 x 100 = 345 g

• Mass = 1.5 x 2.3 x 90 = 310.5 g