
Understanding Electric Charge and Field

Quiz
•
Physics
•
12th Grade
•
Hard
ATOMIC ACHIEVERS
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20 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is Coulomb's Law and how is it mathematically expressed?
F = k * (q1 + q2) / r
F = k * |q1 * q2| * r^2
F = k * |q1 * q2| / r^2
F = k * (q1 - q2) / r
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Calculate the force between two charges of +3 µC and -2 µC separated by a distance of 0.5 m using Coulomb's Law.
0.045 N
0.10788 N
0.215 N
0.300 N
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Explain the significance of the electrostatic constant in Coulomb's Law.
The electrostatic constant is significant as it quantifies the strength of the electrostatic force in Coulomb's Law.
It is only relevant in magnetic fields.
It determines the mass of charged particles.
It has no impact on the distance between charges.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the principle behind Gauss's Law?
The electric flux through a closed surface is proportional to the enclosed charge.
The electric field is constant throughout a closed surface.
The total charge is always zero in any closed surface.
The magnetic flux through a closed surface is proportional to the enclosed charge.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
State Gauss's Law in mathematical form.
∮ E · dA = ε₀ / Q_enc
∮ E · dA = Q_enc / ε₀
E = Q_enc / (4πε₀r²)
∮ E · dA = 0
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How can Gauss's Law be applied to find the electric field due to a uniformly charged sphere?
E = Q/(4πε₀r²) for r > R; E = 0 for r < R
E = Q/(4πε₀r³) for all r
E = 0 for r > R; E = Q/(4πε₀r²) for r < R
E = Q/(2πε₀r) for r > R; E = Q/(4πε₀R²) for r < R
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Describe the relationship between electric field and electric flux as per Gauss's Law.
Electric field is independent of electric flux.
Electric flux is the same as electric potential.
Electric flux is proportional to the electric field and the area through which it passes, as described by Gauss's Law.
Electric field decreases with increasing area.
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