Area and Perimeter of Rectangles

What is the perimeter of the rectangle?

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Answer explanation

The answer is 6.

When I want to find the perimeter of a rectangle, I add the lengths of all of the sides.

If I add all of the lengths of the sides of the rectangle, I solve the equation 1+1+2+2=6.

Tags

CCSS.4.MD.A.3

What is the area of the rectangle?

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Answer explanation

The answer is 6.

When I want to find the area of a rectangle, I multiply the lengths of the length and width.

If I multiply the length (3) by the width (2) of the rectangle, I solve the equation 2x3=6.

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

What is the perimeter of this square?

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Answer explanation

The answer is 40.

When I want to find the perimeter of a square, I add the lengths of all of the sides. Each side of a square is the same length.

If I add all of the lengths of the sides of the square, I solve the equation 10+10+10+10=40.

Tags

CCSS.4.MD.A.3

What is the area of the rectangle?

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Answer explanation

The answer is 32.

When I want to find the area of a rectangle, I multiply the length and the width.

If I multiply the length (8) and and the width (4), I solve the equation 8x4=32.

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

What is the perimeter of the rectangle?

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Answer explanation

The answer is 22.

When I want to find the perimeter of a rectangle, I add the lengths of all of the sides.

If I add all of the lengths of the sides of the rectangle, I solve the equation 5+5+6+6=22.

Tags

CCSS.4.MD.A.3

What is the area of the square?

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Answer explanation

The answer is 1,521.

When I want to find the area of a square, I multiply the length and width. All sides of a square are equal, so the length and width are the same.

If I multiply all of the length (39) and width (39), I solve the equation 39x39=1,521.

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

The length of the rectangle is 4 meters. The area is 8 square meters. What is the width of the rectangle?

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Answer explanation

The answer is 2.

When I want to find the length of a missing side of a rectangle and I know the length of one side and the area of the rectangle, I need to divide the area by the length of the side.

I know that doing this will give me the length of the missing side because it's the opposite of how I find the area when I know the length and width.

If I divide the area (8) by the length of the known side (4), I solve the equation 8 divided by 4 equals 2.

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

The perimeter of the rectangle is 26 yards and the two missing sides have the same length. What is the length of one of the missing sides?

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Answer explanation

The answer is 8.

When I know the perimeter of a rectangle and the length of two of the sides, I can add the lengths of the known sides and subtract them from the perimeter. This will tell me what length remains.

Then, I need to divide this length by 2 because there are 2 equal sides that are sharing this value.

If I add the two known sides (5 and 5), I get 10. If I subtract 10 from the perimeter (26), I solve the equation 26-10=16.

The length shared by the two unknown sides is 16. When I divide 16 by 2, I learn that each unknown side has a length of 8 inches.

Tags

CCSS.4.MD.A.3

What is the area of the rectangle?

Only type the number.

Answer explanation

The answer is 8.

When I need to find the area of a rectangle, I multiply the length and width.

If I multiply the length (2) and width (4) of this rectangle, I solve the equation 2x4=8.

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

The perimeter of the rectangle is 22 inches and the two missing sides have the same length. What is the length of one of the missing sides?

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Answer explanation

The answer is 5.

When I need to find the length of an unknown side of a rectangle but I know the perimeter and the length of 2 other sides, I can add the lengths of the two known sides and then subtract that total from the perimeter.

Then, I need to divide this remaining length by 2 to find the length of 1 of the missing sides.

If I add the length of the known sides of the rectangle (6 and 6), I get 12. When I subtract 12 from the perimeter (22), I get a difference of 10.

If I divide the remaining length of 10 by 2, I learn that each of the unknown sides are 5 inches long.

Tags

CCSS.4.MD.A.3