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Matematik mantiq

Authored by gulshan ashurova

Mathematics

University

Used 3+ times

Matematik mantiq
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40 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Berilgan: U={0,1,2,3,4,5,6,7,8,9}, A={1,2,3}, B={2,3,4,5}, A\B ni to'ldiruvchisini toping

{0,1,2,3,4,5}

{6,7,8,9}

{0,2,3,4,5,6,7,8,9}

{1,2,3,4,5}

2.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

A va B bo'sh bo'lmagan to'plamlar bo'lsin A ⊂\subset B u holda quyidagilardan qaysi bo'sh to'plam bo'ladi?

A\B

A ∪\cup B

A ∩\cap B

A ∪B‾\cup\overline{B}

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Berilgan mulohazani formula ko'rinishida ifodalang: "Agar harorat noldan yuqori bo'lsa , unda muz eriydi va daraxt bo'lagi suzadi"

A→BA\rightarrow B

A ∧\wedge B

A↔BA\leftrightarrow B

A→(B∧C)A\rightarrow\left(B\wedge C\right)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Berilgan mulohazani formula ko'rinishida ifodalang:"Son juft bo'ladi faqat va faqat shunda , qachonki u ikkiga bo'linsa"

A↔BA\leftrightarrow B

A →\rightarrow B

A∧BA\wedge B

A‾ ∧B \overline{A}\ \wedge B\

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Berilgan mulohazani formula ko'rinishida ifodalang:"Agar talaba bilet javoblarini bilsa va qo'shimcha savollarga javob bersa , unda u besh baho oladi."

(A∧B)→C\left(A\wedge B\right)\rightarrow C

(A‾ ∧B)→C\left(\overline{A}\ \wedge B\right)\rightarrow C

A→(B∧C‾)A\rightarrow\left(B\wedge\overline{C}\right)

A↔BA\leftrightarrow B

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Quyidagi belgilar ketma-ketliklarining qaysi biri formula bo'ladi?

((B→(A∧C))∧(A∨C)‾)\left(\left(B\rightarrow\left(A\wedge C\right)\right)\wedge\overline{\left(A\vee C\right)}\right)

(A→∨(B∧C))\left(A\rightarrow\vee\left(B\wedge C\right)\right)

((A‾ ∨C)∧A,D)\left(\left(\overline{A}\ \vee C\right)\wedge A,D\right)

(A→B)∨→C\left(A\rightarrow B\right)\vee\rightarrow C

7.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Quyidagi belgilar ketma-ketliklarining qaysi biri formula bo'lmaydi?

((→B∨C)∧A,D)\left(\left(\rightarrow B\vee C\right)\wedge A,D\right)

(A↔B)∧A‾\left(A\leftrightarrow B\right)\wedge\overline{A}

(B∧C)∧(A∨D)\left(B\wedge C\right)\wedge\left(A\vee D\right)

(A→B)∧C\left(A\rightarrow B\right)\wedge C

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