Oxidation States and Chemical Compounds

The video tutorial explains how to determine the oxidation number of carbon in CF2Cl2 (dichlorodifluoromethane). It begins by noting that the compound is neutral, meaning the sum of oxidation numbers is zero. The tutorial identifies fluorine as having an oxidation state of -1 and chlorine as -1 when bonded to carbon. An equation is set up to solve for carbon's oxidation number, resulting in a value of +4. The tutorial concludes by verifying that the sum of oxidation numbers equals zero, confirming the calculations.

What is the overall charge of the compound CF2Cl2?

• Depends on the environment

• Neutral

• Negative

• Positive

What is the oxidation state of fluorine in most compounds?

• 0

• +1

• -1

• +2

In which group is chlorine found, and what is its usual oxidation state?

• Group 18, 0

• Group 15, -3

• Group 17, -1

• Group 16, -2

How many fluorine atoms are present in CF2Cl2?

• 2

• 1

• 4

• 3

What equation is set up to find the oxidation number of carbon in CF2Cl2?

• x + 4 = 0

• x - 4 = 0

• x + 2 = 0

• x - 2 = 0

What is the oxidation number of carbon in CF2Cl2?

• +2

• +4

• +3

• +5

How do the oxidation numbers of all atoms in CF2Cl2 add up?

• They add up to 0

• They add up to -2

• They add up to +2

• They add up to +4

What is the sum of the oxidation numbers of the two fluorine atoms in CF2Cl2?

• -2

• -1

• 0

• +2

What is the sum of the oxidation numbers of the two chlorine atoms in CF2Cl2?

• -2

• +2

• 0

• -1