Oxidation Numbers and Iodine Compounds

This video tutorial explains how to determine the oxidation numbers for iodine in the ion H4IO6-. It begins by discussing the concept of oxidation numbers and their significance in ions. The tutorial then focuses on the specific ion H4IO6-, explaining the expected oxidation numbers for hydrogen and oxygen. An equation is set up to solve for the unknown oxidation number of iodine, considering the overall charge of the ion. The video concludes by solving the equation, revealing that the oxidation number of iodine is +7, and summarizing the process.

What is the charge of the ion H4IO6-?

• 0

• +1

• -2

• -1

What is the oxidation number of hydrogen in H4IO6-?

• +1

• -1

• +2

• 0

Why is iodine's expected oxidation number not -1 in H4IO6-?

• Because it is bonded to oxygen

• Because it is in group 16

• Because it is a metal

• Because it is a noble gas

What is the typical oxidation number of oxygen in compounds?

• -1

• 0

• +2

• -2

How many oxygen atoms are present in H4IO6-?

• 4

• 6

• 5

• 7

What is the oxidation number of iodine in H4IO6- after solving the equation?

• +5

• +6

• +7

• +8

What is the sum of oxidation numbers in H4IO6- supposed to equal?

• -2

• +1

• 0

• -1

What is the final verification step after finding the oxidation number of iodine?

• Checking the periodic table

• Recalculating the oxidation number of hydrogen

• Adding up all oxidation numbers to match the ion's charge

• Rewriting the chemical formula