Oxidation Numbers in Complex Compounds

This video tutorial explains how to find the oxidation numbers for gold in the compound NaAu(CN)2, known as sodium dicyanoaurate. It begins by establishing that the compound is neutral, meaning the oxidation numbers must sum to zero. The tutorial identifies sodium's oxidation number as +1 and sets up an equation to solve for gold's oxidation number, considering the cyanide ion's charge. The calculation reveals that gold's oxidation number is +1. The video concludes by verifying the results and providing additional resources for understanding the oxidation numbers of carbon and nitrogen in cyanide.

What is the oxidation number of sodium in NaAu(CN)2?

• 0

• +2

• +1

• -1

In the compound NaAu(CN)2, what is the oxidation number of gold represented as?

• y

• x

• z

• w

What is the charge of the cyanide ion (CN) in NaAu(CN)2?

• +1

• +2

• -1

• 0

How do the oxidation numbers in the cyanide ion add up?

• To zero

• To +1

• To -1

• To +2

What equation is set up to find the oxidation number of gold in NaAu(CN)2?

• x + 2 = 0

• x - 1 = 0

• x + 1 = 0

• x - 2 = 0

What is the oxidation number of gold in NaAu(CN)2?

• +1

• +2

• -1

• 0

What is the total oxidation number for the entire compound NaAu(CN)2?

• +2

• -1

• 0

• +1

What is the oxidation number of carbon in the cyanide ion?

• -2

• +2

• -4

• +4

What is the oxidation number of nitrogen in the cyanide ion?

• +3

• -3

• +1

• -1

Where can you find additional resources for understanding oxidation numbers in cyanide ions?

• In the video description

• In the textbook

• In the appendix

• In the glossary