Lewis Structures and Valence Electrons

The video tutorial explains how to write the Lewis structure for xenon dibromide (XeBr2). It begins by counting the valence electrons: xenon has 8 and each bromine has 7, totaling 22 electrons. Xenon is placed in the center with bromine on either side. Electrons are placed to form bonds and complete the octet for bromine. The structure initially uses 20 electrons, so the remaining two are added to xenon, which can have an expanded octet. The final structure shows each bromine with an octet and xenon with more than eight electrons.

How many valence electrons does xenon have in the Lewis structure of XeBr2?

• 12

• 8

• 6

• 10

What is the total number of valence electrons used in the Lewis structure of XeBr2?

• 20

• 22

• 18

• 24

Which element is placed at the center of the Lewis structure for XeBr2?

• Bromine

• Xenon

• Oxygen

• Hydrogen

How many pairs of electrons are initially placed between xenon and each bromine atom?

• 4

• 3

• 2

• 1

What is the purpose of completing the octet on bromine in the Lewis structure?

• To increase stability

• To reduce reactivity

• To form ionic bonds

• To balance charges

How many valence electrons are left after completing the octet on bromine in XeBr2?

• 2

• 3

• 0

• 1

What allows xenon to accommodate more than eight electrons in its valence shell?

• Its small size

• Its high electronegativity

• Its ability to form double bonds

• Its capacity for an expanded octet

What is the final electron configuration around xenon in the Lewis structure of XeBr2?

• 8 electrons

• 10 electrons

• 12 electrons

• 14 electrons