
Balancing Chemical Equations
Interactive Video
•
Chemistry
•
9th - 10th Grade
•
Practice Problem
•
Hard
Emma Peterson
FREE Resource
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7 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What are the initial counts of hydrogen, nitrogen, oxygen, and sodium atoms on the reactant side of the equation?
1 hydrogen, 1 nitrogen, 3 oxygens, 1 sodium
2 hydrogens, 1 nitrogen, 3 oxygens, 1 sodium
1 hydrogen, 2 nitrogens, 3 oxygens, 2 sodiums
2 hydrogens, 2 nitrogens, 6 oxygens, 2 sodiums
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you balance the hydrogen atoms in the equation?
Add a coefficient of 2 in front of HNO3
Add a coefficient of 2 in front of Na
Add a coefficient of 3 in front of NaNO3
Add a coefficient of 3 in front of HNO3
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the effect of adding a coefficient of 2 in front of HNO3?
It balances the hydrogen and nitrogen atoms
It balances only the hydrogen atoms
It balances the hydrogen, nitrogen, and oxygen atoms
It balances the hydrogen and oxygen atoms
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you balance the oxygen atoms in the equation?
Add a coefficient of 2 in front of Na
Add a coefficient of 2 in front of NaNO3
Add a coefficient of 3 in front of HNO3
Add a coefficient of 3 in front of NaNO3
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the result of adding a coefficient of 2 in front of NaNO3?
It balances only the oxygen atoms
It balances the nitrogen and oxygen atoms
It balances the nitrogen, oxygen, and sodium atoms
It balances the nitrogen and sodium atoms
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the sodium atom balanced in the equation?
By adding a coefficient of 3 in front of NaNO3
By adding a coefficient of 2 in front of NaNO3
By adding a coefficient of 3 in front of Na
By adding a coefficient of 2 in front of Na
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final balanced equation for the reaction between nitric acid and sodium?
2HNO3 + Na → NaNO3 + H2
HNO3 + 2Na → NaNO3 + H2
2HNO3 + 2Na → 2NaNO3 + H2
HNO3 + Na → NaNO3 + H2
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