Barium and Sulfur Compounds

The video tutorial explains how to write the Lewis structure for barium sulfide (BaS). It begins by identifying barium as a metal and sulfur as a non-metal, forming an ionic compound. The tutorial details how valence electrons are transferred from barium to sulfur, completing the octet for sulfur and resulting in stable electron configurations. Barium loses two electrons, gaining a 2+ charge, while sulfur gains two electrons, acquiring a 2- charge. The charges balance to zero, making BaS a neutral compound. Brackets are used to indicate the transfer of electrons, emphasizing the ionic nature of the bond.

What type of compound is formed when a metal and a non-metal combine?

• Covalent compound

• Ionic compound

• Metallic compound

• Molecular compound

How many valence electrons does barium have?

• Six

• Eight

• Two

• One

In which group of the periodic table is sulfur found?

• Group 1

• Group 8

• Group 6A

• Group 2

What happens to the valence electrons of barium in the formation of BaS?

• They are lost to the environment

• They remain with barium

• They are transferred to sulfur

• They are shared with sulfur

What is the charge on sulfur after it gains electrons from barium?

• 2+

• 0

• 2-

• 1-

Why is BaS considered a neutral compound?

• Because the charges on barium and sulfur cancel each other out

• Because it has an equal number of protons and electrons

• Because it has no ions

• Because it is a covalent compound

What is the purpose of using brackets in the Lewis structure of BaS?

• To separate the ions

• To highlight the metal

• To show the transfer of electrons

• To indicate shared electrons

What type of bond is formed between barium and sulfur in BaS?

• Hydrogen bond

• Covalent bond

• Ionic bond

• Metallic bond

Which of the following best describes the electron configuration of sulfur after forming BaS?

• It has a full outer shell

• It has an incomplete octet

• It shares electrons with barium

• It loses electrons to barium