Oxidation Numbers in HNO3

This video tutorial explains how to determine the oxidation number of nitrogen in nitric acid (HNO3). It begins by discussing the concept of oxidation numbers and the neutrality of compounds. The video then demonstrates the calculation of oxidation numbers for hydrogen, oxygen, and nitrogen in HNO3, showing that the sum equals zero. An algebraic method is also presented to find the oxidation number of nitrogen, confirming it as +5. The tutorial concludes with a summary of the findings.

What is the oxidation number of hydrogen when it is bonded to nonmetals?

• +1

• -1

• 0

• +2

What is the typical oxidation number of oxygen in compounds?

• 0

• -1

• +2

• -2

In HNO3, what is the total oxidation number contributed by the three oxygen atoms?

• +6

• +3

• -3

• -6

What is the oxidation number of nitrogen in HNO3 to balance the compound to zero?

• +3

• -5

• +5

• -3

What is the result when you add the oxidation numbers of all atoms in HNO3?

• -1

• 0

• +1

• +5

How can the oxidation number of nitrogen in HNO3 be determined algebraically?

• By ignoring the oxidation numbers of other elements

• By setting up an equation with x for nitrogen

• By considering nitrogen as a noble gas

• By assuming nitrogen is -3

What is the algebraic expression for the oxidation number of nitrogen in HNO3?

• x + 1 - 6 = 0

• x - 1 + 6 = 0

• x - 2 + 6 = 0

• x + 2 - 6 = 0

What is the final oxidation number of nitrogen in HNO3 as concluded in the video?

• +5

• -3

• -5

• +3