Inverse Functions and Area Calculations

Inverse Functions and Area Calculations

Assessment

Interactive Video

Mathematics

11th - 12th Grade

Hard

Created by

Lucas Foster

FREE Resource

The video tutorial covers the concepts of domain and range using the sine inverse function, graphing the function, finding its inverse, and calculating the area bounded by the curve. It provides a step-by-step approach to understanding these mathematical concepts, emphasizing the importance of switching variables and changing the subject when finding inverse functions. The tutorial also guides on calculating areas using integration, highlighting common mistakes and providing solutions.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the domain of a regular sine inverse function?

From -π/2 to π/2

From 0 to π

From -1 to 1

From -2 to 2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How does the modification of '2x' affect the domain of the sine inverse function?

It shifts the domain to the right

It halves the domain range

It does not affect the domain

It doubles the domain range

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What should be present at the ends of a sine inverse curve?

Horizontal tangents

Vertical tangents

No tangents

Diagonal tangents

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in finding an inverse function?

Switch the input and output variables

Change the subject of the equation

Differentiate the function

Graph the function

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When finding an inverse function, what can be done in any order?

Integrating and differentiating

Scaling and translating

Switching variables and changing the subject

Graphing and differentiating

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the boundary value given for the area calculation?

x = 1

x = 0

x = -1

x = -1/2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it more useful to calculate the area using subtraction?

Because it simplifies the graph

Because the area to subtract is already known

Because it avoids integration

Because it is a faster method

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