Practice - Graphing Quadratic functions in vertex form

Does the graph of

-2(x + 5)² + 2

have a minimum or a maximum?

• Minimum

• Maximum

• It has neither.

• It has both.

Given: y = 2(x - 5)² + 6, the vertex is

• (2,-5)

• (-5,6)

• (2,6)

• (5,6)

Which equation is graphed above?

• $y=-\left(x-1\right)^2+4$

• $y=\left(x-1\right)^2+4$

• $y=-\left(x-4\right)^2+1$

• $y=\left(x-4\right)^2+1$

Which equations matches the graph above?

• 
• 
• 
• 

Which equation matches the  graphed above?

• $p\left(x\right)=\left(x-1\right)^2+4$

• $p\left(x\right)=\left(x-4\right)+1$

• $p\left(x\right)=-\left(x+1\right)^2-4$

• $p\left(x\right)=-\left(x+4\right)\ ^2-1$

Which equation matches the graph above?

• $r\left(x\right)=-\left(x+4\right)^2-1$

• $r\left(x\right)=\left(x+4\right)^2-1$

• $r\left(x\right)=-\left(x-4\right)^2+1$

• $r\left(x\right)=\left(x-4\right)^2+1$

Which equation matches the graph?

• $f\left(x\right)=\left(x-1\right)^2+4$

• $f\left(x\right)=\left(x+4\right)^2-1$

• $f\left(x\right)=-\left(x-1\right)^2+4$

• $f\left(x\right)=-\left(x+4\right)^2-1$

Which way does the following equation open? $f\left(x\right)=-\frac{1}{2}\left(x-5\right)^2+6$  

• upward

• downward

What is the vertex of the following equation? $f\left(x\right)=-\frac{1}{2}\left(x-5\right)^2+6$  

•  $\left(-5,-6\right)$  

•  $\left(-5,6\right)$  

•  $\left(5,-6\right)$  

•  $\left(5,6\right)$