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Electrical Engineering Quiz

Authored by Hashim Ramos

Mathematics

University

Electrical Engineering Quiz
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60 questions

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1.

MULTIPLE CHOICE QUESTION

5 mins • 4 pts

Given the following phase currents: Ia = 3.5 + j3.5; Ib = - j3; Ic = -2.6 + j1.5. Determine the negative sequence current for phase A.

-0.313 - j0.678

0.313 + j0.678*

-0.313 + j0.678

0.313 - j.0.678

2.

MULTIPLE CHOICE QUESTION

5 mins • 4 pts

Heating value of coal largely depends on

Moisture content

Ash content*

Volatile matter

Size of coal particles

3.

MULTIPLE CHOICE QUESTION

5 mins • 4 pts

Which of the following will take least time in starting from cold condition to full load operation? (Note: Twice lumabas)

Gas turbine plant

Hydro-electric power plant*

Nuclear power plant

Thermal power plant

4.

MULTIPLE CHOICE QUESTION

5 mins • 4 pts

Which of the following cannot have a single unit of 100 MW?

Diesel power plant*

Hydro power plant

Steam power plant

Nuclear power plant

5.

MULTIPLE CHOICE QUESTION

5 mins • 4 pts

A 69kV three-phase transposed line is composed of one ACSR 336, 400 cmil, 26/7 linnet conductor per phase with a horizontal configuration of D12 = 5 ft, D23 = 5 ft, and D13 = 10 ft. The conductors have a diameter of 0.72 inch and a GMR of 0.0243 ft. Find the inductance per phase per kilometer of the line.

1.0963 mH/km

1.1116 mH/km*

1.1505 mH/km

1.1233 mH/km

6.

MULTIPLE CHOICE QUESTION

5 mins • 4 pts

A series circuit consists of three resistors R1, R2, and R3 which are connected to a 240-V source. If the voltage drop across R1 is 60-V when the current is 4A and R2 = 1.5R3, what is the ohmic resistance R3?

15

18*

27

28

7.

MULTIPLE CHOICE QUESTION

5 mins • 4 pts

A load consists of a resistance R in parallel with a capacitor of reactance X. The load is fed from a single phase supply through a line of impedance 8.4 + j11.2 ohms. The rms voltage at the load terminal is 1200 at 0 degrees V rms, and the load is taking 30 kVA at 0.8 power factor leading. Find the supply voltage.

1.2 + j0.35 kV*

1.2 - j0.35 kV

1.536 - j0.098 kV

1.536 + j0.098 kV

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