f ( x ) = x , D f ( x ) = ? f\left(x\right)=\sqrt{x},\ Df\left(x\right)=? f ( x ) = x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> , D f ( x ) = ?

f ′ ( x ) = 1 2 x f'\left(x\right)=\frac{1}{2\sqrt{x}} f ′ ( x ) = 2 x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

f ′ ( x ) = 2 x f'\left(x\right)=2\sqrt{x} f ′ ( x ) = 2 x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

f ′ ( x ) = 1 x f'\left(x\right)=\frac{1}{\sqrt{x}} f ′ ( x ) = x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

f ′ ( x ) = − 1 x f'\left(x\right)=-\frac{1}{\sqrt{x}} f ′ ( x ) = − x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

f ( x ) = x − 2 s e n x f\left(x\right)=x-2senx f ( x ) = x − 2 s e n x , D f ( x ) = ? Df\left(x\right)=? D f ( x ) = ?

f ′ ( x ) = 1 − 2 cos ⁡ x f'\left(x\right)=1-2\cos x f ′ ( x ) = 1 − 2 cos x

f ′ ( x ) = 2 cos ⁡ x f'\left(x\right)=2\cos x f ′ ( x ) = 2 cos x

f ′ ( x ) = 1 + cos ⁡ x f'\left(x\right)=1+\cos x f ′ ( x ) = 1 + cos x

f ′ ( x ) = 2 − cos ⁡ x f'\left(x\right)=2-\cos x f ′ ( x ) = 2 − cos x

f ( x ) = 2 ln ⁡ x + s e n x + 1 , D f ( x ) = ? f\left(x\right)=2\ln x+senx+1,\ Df\left(x\right)=? f ( x ) = 2 ln x + s e n x + 1 , D f ( x ) = ?

f ′ ( x ) = 2 x + cos ⁡ x f'\left(x\right)=\frac{2}{x}+\cos x f ′ ( x ) = x 2 + cos x

f ′ ( x ) = 2 x + cos ⁡ x f'\left(x\right)=2x+\cos x f ′ ( x ) = 2 x + cos x

f ′ ( x ) = 2 x − cos ⁡ x f'\left(x\right)=\frac{2}{x}-\cos x f ′ ( x ) = x 2 − cos x

f ′ ( x ) = 2 x + s e n x f'\left(x\right)=2x+senx f ′ ( x ) = 2 x + s e n x

f ( x ) = e x + x , D f ( x ) = ? f\left(x\right)=e^x+x\ ,\ Df\left(x\right)=? f ( x ) = e x + x , D f ( x ) = ?

f ′ ( x ) = e x + 1 f'\left(x\right)=e^x+1 f ′ ( x ) = e x + 1

f ( x ) = 2 e + 1 f\left(x\right)=2e+1 f ( x ) = 2 e + 1

f ′ ( x ) = 2 e x + 1 f'\left(x\right)=2e^x+1 f ′ ( x ) = 2 e x + 1

f ′ ( x ) = e x f'\left(x\right)=e^x f ′ ( x ) = e x

f ( x ) = x + ln ⁡ x f\left(x\right)=x+\ln x f ( x ) = x + ln x

f ′ ( x ) = 1 + 1 x f'\left(x\right)=1+\frac{\text{1}}{\text{x}} f ′ ( x ) = 1 + x 1

f ′ ( x ) = x + 1 x f'\left(x\right)=\frac{x+1}{x} f ′ ( x ) = x x + 1

f ′ ( x ) = x + 1 f'\left(x\right)=x+1 f ′ ( x ) = x + 1

f ′ ( x ) = x − 1 x f'\left(x\right)=x-\frac{1}{x} f ′ ( x ) = x − x 1

f ( x ) = sin ⁡ x + cos ⁡ x f\left(x\right)=\sin x+\cos x f ( x ) = sin x + cos x

f ′ ( x ) = cos ⁡ x − sin ⁡ x f'\left(x\right)=\cos x-\sin x f ′ ( x ) = cos x − sin x

f ′ ( x ) = cos ⁡ x + sin ⁡ x f'\left(x\right)=\cos x+\sin x f ′ ( x ) = cos x + sin x

f ′ ( x ) = − cos ⁡ x + sin ⁡ x f'\left(x\right)=-\cos x+\sin x f ′ ( x ) = − cos x + sin x

f ′ ( x ) = − cos ⁡ x − sin ⁡ x f'\left(x\right)=-\cos x-\sin x f ′ ( x ) = − cos x − sin x

Primi esercizi sulle derivate Quiz

23 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

La derivata di una funzione in un punto, se esiste, è:

Un numero

Una funzione

Un angolo

La retta tangente alla funzione in quel punto

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Le seguenti funzioni hanno la stessa derivata, tranne una. Quale?

y=x^0,5+1

y=x^0,5-1

y=x^0,5+2x

y=x^0,5

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

La derivata della funzione y=cos(ln(x)) è:

y'=-sin(1/x)

y'=cos(1/x)

y'=-sin(ln (x))

y'=-(1/x)sin(ln(x))

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

La derivata di y=e^x⋅cos(x) è:

y'=e^x⋅(cos(x)+sin(x))

y'=e^x⋅(cos(x)-sin(x))

y'=e^x⋅(cos(2x))

y'=cos(x)⋅(e^x-sin(x))

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Sia f(x)=2x²-3x+1. Calcola il valore della derivata seconda di f(x) nel punto x=1

8

4

3

1

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Sia f(x)=(2x-1)^0,5. Calcola il valore della derivata prima nel punto x=5

5

1/3

2/3

1/6

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Sia f(x)=5x-x². Quanto vale la pendenza della retta tangente al grafico di f(x) nel punto A(2,6)?

1/2

1

3/2

2

9.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$f\left(x\right)=\frac{\text{1}}{\text{x}}$ , $Df\left(x\right)=?$

$f'\left(x\right)=\frac{1}{x}$

$f'\left(x\right)=-\frac{1}{\text{}x^2}$

$f'\left(x\right)=\frac{1}{\text{x}^2}$

$f'\left(x\right)=-\frac{1}{x}$

10.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$f\left(x\right)=\sqrt{x},\ Df\left(x\right)=?$

$f'\left(x\right)=2\sqrt{x}$

$f'\left(x\right)=\frac{1}{\sqrt{x}}$

$f'\left(x\right)=\frac{1}{2\sqrt{x}}$

$f'\left(x\right)=-\frac{1}{\sqrt{x}}$

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Primi esercizi sulle derivate

La derivata di una funzione in un punto, se esiste, è:

Le seguenti funzioni hanno la stessa derivata, tranne una. Quale?

La derivata della funzione y=cos(ln(x)) è:

La derivata di y=ex⋅cos(x) è:

Sia f(x)=2x2-3x+1. Calcola il valore della derivata seconda di f(x) nel punto x=1

Sia f(x)=(2x-1)0,5. Calcola il valore della derivata prima nel punto x=5

Sia f(x)=5x-x². Quanto vale la pendenza della retta tangente al grafico di f(x) nel punto A(2,6)?

Sia y=5x. Calcola y'

f(x)=1xf\left(x\right)=\frac{\text{1}}{\text{x}}f(x)=x1​ , Df(x)=?Df\left(x\right)=?Df(x)=?

f(x)=x, Df(x)=?f\left(x\right)=\sqrt{x},\ Df\left(x\right)=?f(x)=x​, Df(x)=?

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

La derivata di y=e^x⋅cos(x) è:

Sia f(x)=2x²-3x+1. Calcola il valore della derivata seconda di f(x) nel punto x=1

Sia f(x)=(2x-1)^0,5. Calcola il valore della derivata prima nel punto x=5

Sia y=5^x. Calcola y'

$f\left(x\right)=\frac{\text{1}}{\text{x}}$ , $Df\left(x\right)=?$

$f\left(x\right)=\sqrt{x},\ Df\left(x\right)=?$