Solving Radical Equations and Verification

Solving Radical Equations and Verification

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains how to solve a radical equation involving square roots. The instructor begins by introducing the problem and then demonstrates the process of squaring both sides to eliminate the square root. The solution involves using reciprocals and verifying the result by substituting back into the original equation. The tutorial also covers power manipulation techniques to simplify expressions and concludes with a final confirmation of the solution.

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19 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the radical equation presented in the video?

Divide both sides by 2

Square both sides

Subtract 2 from both sides

Add 2 to both sides

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of squaring both sides of the equation initially?

To eliminate the square root

To make the equation quadratic

To add complexity

To simplify the equation

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After squaring both sides of the equation, what is the resulting expression?

x^3 = 4

x * sqrt(x) = 4

x^2 = 4

x = 4

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the expression x * sqrt(x) = 4 represent in the solution process?

An intermediate step

A verification step

The original problem

The final solution

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What mathematical operation is used to eliminate the power of three in the equation?

Adding 3

Multiplying by the reciprocal

Dividing by 3

Multiplying by 3

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the reciprocal used in the solution process?

To verify the solution

To simplify the equation

To eliminate the power of three

To add complexity

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the expression 16^(1/3) verified in the video?

By taking the cube root

By squaring it

By multiplying by 16

By substituting back into the original equation

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