EOY: Scaling

$$\frac{1}{8}$$

$$\frac{1}{3}$$

$$\frac{4}{4}$$

$$\frac{6}{2}$$

$$\frac{7}{1}$$

$$5\ \frac{1}{3}\times\frac{8}{12}$$

$$5\ \frac{1}{3}\times\frac{3}{3}$$

$$5\ \frac{1}{3}\times\frac{10}{2}$$

$$5\ \frac{1}{3}\times\frac{5}{3}$$

Both Lionel and Naomi

Lionel Only

Naomi Only

Neither Lionel or Naomi

Lionel is multiplying by a factor that is less than 1, so his product will be greater than Naomi's product.

Lionel is multiplying by a factor that is less than 1, so his product will be less than Naomi's product.

Naomi is multiplying by a factor that is less than 1, so her product will be greater than Lionel's

Naomi is multiplying by a factor that is less than 1, so her product will be less than Lionel's

$$1\ \frac{5}{6}\times\frac{5}{6}$$

$$1\ \frac{5}{6}\times\frac{6}{6}$$

$$1\ \frac{5}{6}\times\frac{6}{5}$$

$$1\ \frac{5}{6}\times\frac{11}{6}$$

A

B

C

D

>

<

=

The symbol cannot be determined.

$$2\ \frac{3}{4}\times\frac{3}{6}$$

$$2\ \frac{3}{4}\times\frac{6}{8}$$

$$2\ \frac{3}{4}\times\frac{3}{4}$$

$$2\ \frac{3}{4}\times\frac{3}{2}$$

A

B

C

D

$$\frac{1}{15}\times15$$

$$\frac{11}{12}\times15$$

$$\frac{12}{11}\times15$$

$$\frac{9}{8}\times15$$