
AP Chem Titration Review
Passage
•
Chemistry
•
11th Grade
•
Medium
Corinne Lindemann
Used 48+ times
FREE Resource
15 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the pH of a weak acid calculated?
Use the Henderson-Hasselbalch equation
Use the Ka of the weak acid to solve for [H⁺]
Use the Kb of the weak base to solve for [OH⁻]
Use the pKa to find the pH directly
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the buffer zone before the equivalence point, which equation is used to find the pH?
pH = -log[H⁺]
pH = pKa + log [A⁻]/[HA]
pH = 14 - pOH
pH = -log[OH⁻]
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
At the half-equivalence point of a titration, what is true about the pH?
pH = 7
pH = pKa
pH = 14
pH = 0
Answer explanation
The half-equivalence points occurs when half of the moles of acid have been neutralized. This means the moles of acid are equal to the moles of conjugate base, and pH = pKa.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What happens at the equivalence point in a weak acid and strong base titration?
Only conjugate acid is present
Moles of weak acid are equal to the moles of strong base
Only strong base is present
The solution becomes acidic
Answer explanation
While this is the simplest calculation in a strong acid + strong base titration (it's always 7.0), the equivalence point is the most difficult pH calculation in all other types of titrations.
Check out this video for an example of this type of calculation.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
After the equivalence point, what is used to determine the pH?
The concentration of weak acid
The excess [OH-] in solution from the strong base
The initial concentration of the acid
The concentration of the conjugate acid
6.
DROPDOWN QUESTION
1 min • 1 pt
The (a) of a titration occurs when the moles of acid are equal to the moles of base. The (b) is the point at which the indicator changes color, signifying the end of the titration.
7.
REORDER QUESTION
1 min • 1 pt
Arrange the following acids from weakest to strongest.
Hydrochloric acid (HCl)
pKa = -5.9
Acetic acid (CH3COOH)
pKa = 4.76
Hydrofluoric acid (HF)
pKa = 3.20
Formic acid (HCOOH)
pKa = 3.75
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