
14.6 Acid Base Mixing and Titrating
Authored by Abbey Zaepfel
Chemistry
10th Grade
NGSS covered
Used 1+ times

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23 questions
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1.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
An acid and a base react together and neutralize each other. They always produce:
CO2 and water
a salt and water
CO2 and a salt
CO2 and O2
water and O2
2.
MULTIPLE SELECT QUESTION
2 mins • 1 pt
What are the two products of HCl and NaOH reacting together?
H2O
NaCl
H3O+
OH-
Na2O
3.
MULTIPLE SELECT QUESTION
2 mins • 1 pt
What are the two products of HBr and KOH reacting together?
H2O
KBr
H3O+
OH-
K2O
4.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Calculate the number of moles of H+ (which is also H3O+) in beaker 1.
(0.75)(0.020) = 0.015 mols H+
(0.75)/(0.020) = 37.5 mols H+
(0.020)/(0.75) = 0.0267 mols H+
(0.75)/(20) = 15 mols H+
5.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Calculate the number of moles of OH- in beaker 2.
(0.85)(0.0195) = 0.0166 mols OH-
(0.85)/(0.0195) = 43.6 mols OH-
(0.0195)/(0.85) = 0.0229 mols OH-
(0.85)/(19.5) = 16.6 mols OH-
6.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
From the previous two questions, you should've calculated 0.0150 mols of H+ and 0.0166 mols of OH-.
How much is left over after they react in a 1:1 mole ratio?
0.001575 mols of OH-
0.001575 mols of H+
0.031575 mols of OH-
0.031575 mols of H+
Tags
NGSS.HS-PS1-7
7.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
From previous question, you should've calculated 0.001575 mols of OH- left over. Calculate total volume and find the Molarity of OH-.
Molarity = mols/L
0.001575 / 0.0395 = 0.0399 M OH-
0.001575 / 39.5 = 3.99 x 10-5 M OH-
0.001575 * 0.0395 = 6.22 x 10-5 M OH-
0.0395 / 0.001575 = 25.1 M OH-
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