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14.6 Acid Base Mixing and Titrating

Authored by Abbey Zaepfel

Chemistry

10th Grade

NGSS covered

Used 2+ times

14.6 Acid Base Mixing and Titrating
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23 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

An acid and a base react together and neutralize each other. They always produce:

CO2 and water

a salt and water

CO2 and a salt

CO2 and O2

water and O2

2.

MULTIPLE SELECT QUESTION

2 mins • 1 pt

What are the two products of HCl and NaOH reacting together?

H2O

NaCl

H3O+

OH-

Na2O

3.

MULTIPLE SELECT QUESTION

2 mins • 1 pt

What are the two products of HBr and KOH reacting together?

H2O

KBr

H3O+

OH-

K2O

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Calculate the number of moles of H+ (which is also H3O+) in beaker 1.

(0.75)(0.020) = 0.015 mols H+

(0.75)/(0.020) = 37.5 mols H+

(0.020)/(0.75) = 0.0267 mols H+

(0.75)/(20) = 15 mols H+

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Calculate the number of moles of OH- in beaker 2.

(0.85)(0.0195) = 0.0166 mols OH-

(0.85)/(0.0195) = 43.6 mols OH-

(0.0195)/(0.85) = 0.0229 mols OH-

(0.85)/(19.5) = 16.6 mols OH-

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

From the previous two questions, you should've calculated 0.0150 mols of H+ and 0.0166 mols of OH-.

How much is left over after they react in a 1:1 mole ratio?

0.001575 mols of OH-

0.001575 mols of H+

0.031575 mols of OH-

0.031575 mols of H+

Tags

NGSS.HS-PS1-7

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

From previous question, you should've calculated 0.001575 mols of OH- left over. Calculate total volume and find the Molarity of OH-.

Molarity = mols/L

0.001575 / 0.0395 = 0.0399 M OH-

0.001575 / 39.5 = 3.99 x 10-5 M OH-

0.001575 * 0.0395 = 6.22 x 10-5 M OH-

0.0395 / 0.001575 = 25.1 M OH-

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