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Year 7 Chapter 3B & 3C T2 Week 2

Authored by Zaid Bayraktar

Mathematics

7th Grade

CCSS covered

Used 1+ times

Year 7 Chapter 3B & 3C T2 Week 2
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15 questions

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1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Answer explanation

To find an equivalent fraction, multiply both the numerator and denominator of \(\frac{2}{3}\) by the same number. Multiplying by 2 gives \(\frac{4}{6}\), which is equivalent to \(\frac{2}{3}\).

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Answer explanation

To simplify \( \frac{12}{18} \), find the greatest common divisor (GCD) of 12 and 18, which is 6. Divide both the numerator and denominator by 6: \( \frac{12 \div 6}{18 \div 6} = \frac{2}{3} \). Thus, the correct answer is \( \frac{2}{3} \).

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Answer explanation

To find an equivalent fraction, multiply both the numerator and denominator of \(\frac{5}{8}\) by the same number. Multiplying by 2 gives \(\frac{10}{16}\), which is equivalent. The other options do not simplify to \(\frac{5}{8}\).

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Answer explanation

To convert the mixed number 2\frac{3}{5} to an improper fraction, multiply the whole number (2) by the denominator (5) and add the numerator (3): 2 \times 5 + 3 = 10 + 3 = 13. Thus, the improper fraction is \frac{13}{5}.

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Answer explanation

To convert the improper fraction \( \frac{17}{4} \) to a mixed number, divide 17 by 4. The quotient is 4 and the remainder is 1. Thus, it can be expressed as \( 4 \frac{1}{4} \), which is the correct answer.

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Answer explanation

To simplify \( \frac{18}{24} \), divide both the numerator and denominator by their greatest common divisor, which is 6. This gives \( \frac{18 \div 6}{24 \div 6} = \frac{3}{4} \). Thus, the simplest form is \( \frac{3}{4} \).

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Answer explanation

To convert the mixed number 5\frac{2}{7} to an improper fraction, multiply the whole number (5) by the denominator (7) and add the numerator (2): 5 \times 7 + 2 = 35 + 2 = 37. Thus, the improper fraction is \frac{37}{7}.

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