Physics Practice Review Questions_

Physics Practice Review Questions_

11th Grade

12 Qs

quiz-placeholder

Similar activities

MOMENTUM

MOMENTUM

12th Grade

10 Qs

Momentum+Impulse

Momentum+Impulse

11th - 12th Grade

15 Qs

Newton's 2nd Law of Motion

Newton's 2nd Law of Motion

9th - 12th Grade

15 Qs

Newtons Second Law Ch 5

Newtons Second Law Ch 5

9th - 12th Grade

10 Qs

AP Physics Dynamics

AP Physics Dynamics

11th - 12th Grade

15 Qs

momentum and impulse

momentum and impulse

11th Grade

11 Qs

Work and Energy

Work and Energy

11th Grade

15 Qs

Conservation of Momentum

Conservation of Momentum

11th Grade

10 Qs

Physics Practice Review Questions_

Physics Practice Review Questions_

Assessment

Quiz

Physics

11th Grade

Medium

NGSS
HS-PS2-1, HS-PS2-4, HS-PS2-5

+7

Standards-aligned

Created by

ESTER MEDRANO

Used 7+ times

FREE Resource

12 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

The diagram below shows a glider on an air track with three photogates. Each photogate determines the velocity of the glider as it moves down the air track. Which graph best represents the glider’s velocity as it moves down the air track?

Media Image
Media Image
Media Image
Media Image

Answer explanation

Tags

NGSS.HS-PS2-1

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

A turn on a racetrack is 915 meters long and can be considered a semicircle with a radius of 291 meters. What is the centripetal acceleration of a car that completes the semicircular turn at a constant speed in 15.0 seconds?

0 m/s²

3.14 m/s²

12.8 m/s²

61.0 m/s²

Answer explanation

To find centripetal acceleration, use the formula a = v²/r. First, calculate speed: v = distance/time = 915m/15s = 61m/s. Then, a = (61m/s)² / 291m = 12.8 m/s². Thus, the correct answer is 12.8 m/s².

Tags

NGSS.HS-PS2-1

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A car is traveling at 21.0 m/s. It slows to a stop at a constant rate over 5.00 s. How far does the car travel during those 5.00 seconds before it stops?

4.20 m

52.5 m

105 m

158 m

Answer explanation

To find the distance, use the formula: distance = initial velocity × time + 0.5 × acceleration × time². The car decelerates from 21.0 m/s to 0 m/s in 5.00 s, giving an average speed of 10.5 m/s. Thus, distance = 10.5 m/s × 5.00 s = 52.5 m.

Tags

NGSS.HS-PS2-1

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

The diagram below shows a 6.0 V battery connected to three resistors. How much current is the circuit drawing from the battery?

0.17 A

0.55 A

1.8 A

3.3 A

Answer explanation

To find the current, use Ohm's Law: I = V/R. The total resistance in the circuit is 3.33 ohms (calculated from the resistors). Thus, I = 6.0 V / 3.33 ohms = 1.8 A, which is the correct answer.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Which satellite will experience the same magnitude of gravitational force as Satellite X does in its orbit?

A 1

B 2

C 3

D 4

Answer explanation

Satellite 1 will experience the same magnitude of gravitational force as Satellite X because gravitational force depends on mass and distance from the central body, which are the same for both satellites.

Tags

NGSS.HS-PS2-4

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

A student wants to generate an electric current using a bar magnet and a coil of wire. Possible Laboratory Setups: Lab Setup | Wire Diameter | Number of Loops K | Thin | 200 L | Thin | 100 M | Thick | 200 N | Thick | 100 Which experimental setup will generate the greatest electric current?

Setup K

Setup L

Setup M

Setup N

Answer explanation

Setup M has the thickest wire and the most loops (200), maximizing current generation according to Faraday's law. Thicker wire reduces resistance, and more loops increase the induced voltage, leading to greater current.

Tags

NGSS.HS-PS2-5

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

A student pulled a 100 kg cart up a ramp using a force of 150 N. By the time the cart reached the top of the ramp, it had gained 980 joules of potential energy. What happened to the work the student did by pulling the cart?

Some of the work done on the cart became the cart’s potential energy, and some of the work was converted into heat by friction.

The work done on the cart was equally divided between the cart’s potential and kinetic energy.

All the work done on the cart was transformed into the cart’s potential energy.

The cart had no kinetic energy at the top of the ramp because all the work done on the cart was converted into heat by friction.

Answer explanation

The student did work on the cart, resulting in 980 joules of potential energy. However, not all work was converted to potential energy; some was lost to friction as heat, making the correct choice the first option.

Tags

NGSS.MS-PS2-2

NGSS.MS-PS3-2

NGSS.MS-PS3-4

Create a free account and access millions of resources

Create resources
Host any resource
Get auto-graded reports
or continue with
Microsoft
Apple
Others
By signing up, you agree to our Terms of Service & Privacy Policy
Already have an account?