Molarity Practice Problems

What is the molarity of a solution made by dissolving 5.00 moles of NaCl in 2.00 liters of solution?

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Answer explanation

Molarity (M) is calculated as moles of solute divided by liters of solution. Here, M = 5.00 moles / 2.00 L = 2.50 M. Therefore, the molarity of the solution is 2.50 M.

You have 0.75 moles of HCl dissolved in 0.25 liters of solution. What is the molarity?

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Answer explanation

To find molarity, use the formula M = moles/volume. Here, M = 0.75 moles / 0.25 L = 3 M. Thus, the molarity of the HCl solution is 3 M.

A solution has a molarity of 3.00 M and contains 4.50 moles of KNO₃. What is the volume of the solution in liters?

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Answer explanation

To find the volume, use the formula: Molarity (M) = Moles of solute / Volume (L). Rearranging gives Volume = Moles / Molarity. Thus, Volume = 4.50 moles / 3.00 M = 1.50 L.

How many moles of NaOH are present in 0.50 L of a 1.5 M solution?

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Answer explanation

To find moles, use the formula: moles = molarity × volume. Here, moles = 1.5 M × 0.50 L = 0.75 moles. Thus, there are 0.75 moles of NaOH in the solution.

A student dissolves 2.00 moles of sugar in enough water to make 1.25 L of solution. What is the molarity?

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Answer explanation

Molarity (M) is calculated as moles of solute divided by liters of solution. Here, M = 2.00 moles / 1.25 L = 1.60 M. Thus, the molarity of the solution is 1.60 M.

How many liters of solution are needed to make a 2.0 M solution using 6.0 moles of solute?

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Answer explanation

To find the volume of a 2.0 M solution using 6.0 moles of solute, use the formula: Molarity (M) = moles of solute / liters of solution. Rearranging gives liters = moles / M. Thus, liters = 6.0 moles / 2.0 M = 3.0 liters.

A 1.0 L solution contains 0.20 moles of MgCl₂. What is its molarity?

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Answer explanation

Molarity (M) is calculated as moles of solute per liter of solution. Here, M = 0.20 moles / 1.0 L = 0.20 M. Therefore, the molarity of the MgCl₂ solution is 0.20 M.

Tags

NGSS.HS-PS1-5

What is the molarity of a solution if 0.040 moles of acetic acid (CH₃COOH) are dissolved in 0.080 L of water?

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Answer explanation

Molarity (M) is calculated as moles of solute divided by liters of solution. Here, M = 0.040 moles / 0.080 L = 0.50 M. Thus, the molarity of the acetic acid solution is 0.50 M.

You have 1.2 liters of a 0.50 M H₂SO₄ solution. How many moles of H₂SO₄ are present?

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Answer explanation

To find moles of H₂SO₄, use the formula: moles = molarity × volume. Here, moles = 0.50 M × 1.2 L = 0.60 moles. Thus, there are 0.60 moles of H₂SO₄ present.

How much solute (in moles) is required to make 3.5 L of a 0.80 M NaNO₃ solution?

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Answer explanation

To find the moles of solute, use the formula: moles = molarity × volume. Here, moles = 0.80 M × 3.5 L = 2.8 moles. Therefore, 2.8 moles of NaNO₃ are required.