Which query calculates the average salary per department?

SELECT department_id, AVG(salary) FROM employees GROUP BY department_id;

SELECT AVG(salary) FROM employees;

SELECT department_id, AVG(salary) FROM employees;

SELECT department_id, salary FROM employees GROUP BY salary;

SELECT AVG(salary) GROUP BY department_id FROM employees;

Which query returns employees who earn more than the average salary?

SELECT * FROM employees WHERE salary > (SELECT AVG(salary) FROM employees);

SELECT * FROM employees WHERE salary = AVG(salary);

SELECT AVG(salary) FROM employees WHERE salary > 5000;

SELECT salary FROM employees HAVING salary > AVG(salary);

SELECT * FROM employees JOIN (SELECT AVG(salary) FROM employees);

What is a sequence used for in Oracle SQL?

To generate unique numeric values

Which query creates a view showing employees with salary over 10000?

CREATE VIEW high_salary_employees AS SELECT * FROM employees WHERE salary > 10000;

VIEW high_salary_employees AS SELECT * FROM employees WHERE salary > 10000;

CREATE VIEW FROM employees WHERE salary > 10000;

SELECT * INTO high_salary_employees FROM employees WHERE salary > 10000;

CREATE VIEW high_salary_employees WHERE salary > 10000;

Which query returns the uppercase version of all employee names?

SELECT UPPER(name) FROM employees;

SELECT LOWER(name) FROM employees;

SELECT INITCAP(name) FROM employees;

SELECT REPLACE(name, 'a', 'A') FROM employees;

SELECT SUBSTR(name, 1) FROM employees;

Which query returns employees whose name starts with 'J'?

SELECT * FROM employees WHERE name LIKE '%J';

SELECT * FROM employees WHERE name = 'J%';

SELECT * FROM employees WHERE name CONTAINS 'J';

SELECT * FROM employees WHERE name STARTS WITH 'J';

What is the purpose of a synonym in Oracle?

To create an alias for a database object

Which query creates a synonym for the employees table?

CREATE SYNONYM emp FOR employees;

DEFINE SYNONYM employees AS emp;

Which query selects departments having more than 10 employees?

SELECT department_id FROM employees GROUP BY department_id HAVING COUNT(*) > 10;

SELECT department_id FROM employees WHERE COUNT(*) > 10;

SELECT department_id GROUP BY COUNT(*) > 10;

SELECT department_id HAVING COUNT(*) > 10;

SELECT department_id FROM employees COUNT(*) > 10;

What is the purpose of the INITCAP function in SQL?

Capitalizes the first letter of each word in a string

Returns the number of characters

Which query creates a view of employees in department 10?

CREATE VIEW dept10_employees AS SELECT * FROM employees WHERE department_id = 10;

CREATE VIEW employees WHERE department_id = 10;

CREATE VIEW dept10_employees AS employees IN department 10;

VIEW dept10_employees FROM employees WHERE department_id = 10;

CREATE VIEW dept10_employees FROM employees WHERE department_id = 10;

Which query shows all employees who work in the same department as 'John'?

SELECT * FROM employees WHERE department_id = (SELECT department_id FROM employees WHERE name = 'John');

SELECT * FROM employees WHERE name = 'John' AND department_id IS NOT NULL;

SELECT FROM employees WHERE EXISTS (SELECT FROM employees WHERE name = 'John');

SELECT * FROM employees JOIN departments ON employees.department_id = departments.id WHERE name = 'John';

SELECT * FROM employees WHERE department_id IN (name = 'John');

Which query joins the orders and customers tables using a natural join?

SELECT * FROM orders INNER JOIN customers ON orders.id = customers.id ;

SELECT * FROM orders FULL JOIN customers ON orders.customer_id = customers.customer_id;

SELECT * FROM orders, customers WHERE orders.customer_id = customers.customer_id;

SELECT * FROM orders LEFT OUTER JOIN customers;

Which of the following is the correct use of the COALESCE function?

SELECT COALESCE(NULL, NULL, 'Hello') FROM dual;

SELECT COALESCE('Hello', NULL, NULL) AS greeting;

SELECT COALESCE FROM table_name;

SELECT * FROM COALESCE('x', 'y');

COALESCE('a', 'b') SELECT * FROM dual;

Which query counts the number of employees in each department?

SELECT department_id, COUNT(*) FROM employees GROUP BY department_id;

SELECT COUNT(department_id) FROM employees;

SELECT COUNT(*) GROUP BY department_id FROM employees;

SELECT department_id, COUNT(*) FROM employees;

SELECT COUNT(*) FROM employees WHERE department_id IS NOT NULL;

Which of the following statements about views is TRUE?

Views do not store data physically

Views can insert directly into sequences

Which function combines first and last name with a space in between?

SELECT first_name || ' ' || last_name FROM employees;

SELECT CONCAT(first_name, last_name) FROM employees;

SELECT first_name + last_name FROM employees;

SELECT CONCAT_WS(' ', first_name, last_name) FROM employees;

SELECT first_name & ' ' & last_name FROM employees;

What does the following subquery return? SELECT * FROM employees WHERE salary > (SELECT MAX(salary) FROM employees WHERE department_id = 30);

Employees earning more than the highest salary in department 30

Employees with the highest salary

Employees earning less than average

Which query returns all employees not in department 50?

SELECT * FROM employees WHERE department_id != 50;

SELECT * FROM employees WHERE department_id = 50;

SELECT * FROM employees WHERE department_id NOT IN 50;

SELECT * FROM employees EXCEPT department_id = 50;

SELECT * FROM employees WHERE department_id <> 50;

Which query creates a sequence that increments by 1 and starts at 1?

CREATE SEQUENCE seq1 START WITH 1 INCREMENT BY 1;

CREATE SEQUENCE seq1 BEGIN 1 STEP 1;

CREATE SEQUENCE seq1 VALUES (1, 1);

SEQUENCE seq1 START = 1 INCREMENT = 1;

CREATE NEW SEQUENCE seq1 STARTING AT 1;

What does the TO_CHAR function do in Oracle SQL?

Converts a number or date to a string

Changes the case of a character

Replaces characters in a string

Which query shows the highest salary in each department?

SELECT department_id, MAX(salary) FROM employees GROUP BY department_id;

SELECT department_id, salary FROM employees WHERE salary = MAX(salary);

SELECT MAX(salary) FROM employees;

SELECT department_id FROM employees GROUP BY MAX(salary);

SELECT * FROM employees GROUP BY department_id MAX(salary);

What is the result of this query? SELECT NVL(commission_pct, 0) FROM employees;

Replaces NULL commission values with 0

Shows only non-NULL commissions

What does the DISTINCT keyword do?

Removes duplicate rows from the result

What does this query do? SELECT * FROM employees WHERE REGEXP_LIKE(email, '^[a-zA-Z0-9._%+-]+@ oracle.com $');

Filters emails ending with @ oracle.com using regular expressions

Finds employees without email addresses

Changes email domain to oracle.com

Which query lists all departments that have no employees?

SELECT * FROM departments WHERE department_id NOT IN (SELECT DISTINCT department_id FROM employees);

SELECT FROM departments WHERE NOT EXISTS (SELECT FROM employees);

SELECT * FROM departments WHERE COUNT(employees) = 0;

SELECT department_id FROM employees GROUP BY department_id HAVING COUNT(*) = 0;

SELECT * FROM departments WHERE department_id = 0;

ISYS6892003

Authored by nur anisa

Information Technology (IT)

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MULTIPLE CHOICE QUESTION

20 sec • 1 pt

What is a subquery?

A type of join

A query within another query

A view definition

A sequence generator

A synonym

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which query finds names that end with 'son'?

SELECT * FROM employees WHERE name LIKE '%son%';

SELECT * FROM employees WHERE name LIKE 'son%';

SELECT * FROM employees WHERE name REGEXP_LIKE(name, 'son$');

SELECT * FROM employees WHERE name LIKE '%son';

SELECT * FROM employees WHERE name IN 'son';

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following best defines a view?

A virtual table based on a query

A physical copy of a table

A stored procedure

A trigger function

A synonym for a column

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Which query performs an inner join between orders and customers on customer_id?

SELECT * FROM orders JOIN customers ON orders.id = customers.id;

SELECT * FROM orders FULL JOIN customers;

SELECT * FROM orders NATURAL JOIN customers;

SELECT * FROM orders INNER JOIN customers ON orders.customer_id = customers.customer_id;

SELECT * FROM orders, customers WHERE orders.id = customers.id;

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the UPPER function do in SQL?

Converts all characters to lowercase

Capitalizes the first letter of each word

Removes spaces from a string

Converts all characters to uppercase

Replaces NULL values

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which query creates a sequence starting at 100 and incrementing by 10?

CREATE SYNONYM seq_id FOR 100 INCREMENT 10;

CREATE SEQUENCE seq_id START WITH 100 INCREMENT BY 10;

SEQUENCE seq_id BEGIN 100 STEP 10;

CREATE SEQUENCE seq_id VALUES 100 TO 1000;

START SEQUENCE seq_id AT 100 BY 10;

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Which group function returns the highest value in a column?

MIN

AVG

SUM

MAX

COUNT

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ISYS6892003

What is a subquery?

Which query finds names that end with 'son'?

Which of the following best defines a view?

Which query performs an inner join between orders and customers on customer_id?

What does the UPPER function do in SQL?

Which query creates a sequence starting at 100 and incrementing by 10?

Which group function returns the highest value in a column?

Which query calculates the average salary per department?

Which function is used to search a string with a pattern?

Which query returns employees who earn more than the average salary?

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