Chemistry S2 Final Exam Review

1. Stoichiometry is:

• the calculation of reactants and products in chemical reactions

• the study of motion

• the measurement of temperature

• the process of distillation

Tags

NGSS.HS-PS1-7

Given 5.40 moles of hydrogen, how many moles of water would be produced? (Use the balanced equation: 2 H₂ + 1 O₂ → 2 H₂O)

• 5.40 moles H₂O

• 2.70 moles H₂O

• 10.8 moles H₂O

• 1.80 moles H₂O

Tags

NGSS.HS-PS1-7

Given 12.6 g of oxygen, how many grams of water would be produced? (Use the balanced equation: 2 H₂ + 1 O₂ → 2 H₂O)

• 14.2 g H₂O

• 8.4 g H₂O

• 25.2 g H₂O

• 6.3 g H₂O

What mass of aluminum oxide is produced when 3.65 g of aluminum react with iron(III) oxide?

• 6.89 g Al₂O₃

• 2.45 g Al₂O₃

• 10.12 g Al₂O₃

• 4.32 g Al₂O₃

Tags

NGSS.HS-PS1-7

Limiting reactant is defined as:

• The reactant that is completely consumed in a chemical reaction, thus limiting the amount of product formed.

• The reactant that is present in excess in a chemical reaction.

• The product formed in the largest amount in a chemical reaction.

• The substance that speeds up a chemical reaction without being consumed.

Tags

NGSS.HS-PS1-7

Identify the limiting reactant if 8.27 g of CO and 7.55 g of Fe₂O₃ react in the following equation. (solve for Fe) 3 CO + Fe₂O₃ → 2 Fe + 3 CO₂

• Limiting reactant: CO; Theoretical yield of Fe: 4.90 g

• Limiting reactant: Fe₂O₃; Theoretical yield of Fe: 8.20 g

• Limiting reactant: CO; Theoretical yield of Fe: 7.55 g

• Limiting reactant: Fe₂O₃; Theoretical yield of Fe: 4.90 g

Tags

NGSS.HS-PS1-7

The difference between actual yield and theoretical yield is:

• Actual yield is always greater than theoretical yield.

• Actual yield is the amount actually obtained, while theoretical yield is the maximum possible amount.

• Theoretical yield is always less than actual yield.

• There is no difference between actual yield and theoretical yield.

Determine the percent yield for the reaction between 26.13 g of NH₃ and 30.0 g of oxygen to produce nitrogen monoxide gas and unknown amounts of water.

• 83.6%

• 72.4%

• 91.2%

• 65.8%

Write complete electron configurations for the following elements. Chlorine

• 1s2 2s2 2p6 3s2 3p5

• 1s2 2s2 2p6 3s2 3p6

• 1s2 2s2 2p6 3s2 3p4

• 1s2 2s2 2p6 3s2 3p3

Tags

NGSS.HS-PS1-1

Write complete electron configurations for the following elements. Gold ____________________________________________

• 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p6 7s2 5f14 6d9

• 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d9 6p6

• 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p1

• 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d8 6p6

Tags

NGSS.HS-PS1-1