07.2 - Unit Circle

07.2 - Unit Circle

9th - 12th Grade

29 Qs

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07.2 - Unit Circle

07.2 - Unit Circle

Assessment

Quiz

Mathematics

9th - 12th Grade

Practice Problem

Hard

CCSS
HSG.SRT.C.8, HSF.TF.A.2, HSG.SRT.C.6

+2

Standards-aligned

Created by

Denise Lum

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29 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For θ = 160°, in which quadrant does the terminating ray reside and what is the reference angle θ'?

Quadrant II, 20°

Quadrant III, 70°

Quadrant I, 160°

Quadrant IV, 20°

Answer explanation

For θ = 160°, the angle is in Quadrant II since it is between 90° and 180°. The reference angle θ' is found by subtracting 160° from 180°, giving us 20°. Thus, the correct answer is Quadrant II, 20°.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For θ = 200°, in which quadrant does the terminating ray reside and what is the reference angle θ'?

Quadrant III, 20°

Quadrant II, 20°

Quadrant III, 160°

Quadrant IV, 20°

Answer explanation

For θ = 200°, the angle is in Quadrant III (180° to 270°). The reference angle θ' is found by subtracting 180° from 200°, giving us 20°. Thus, the correct answer is Quadrant III, 20°.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For θ = 310°, in which quadrant does the terminating ray reside and what is the reference angle θ'?

Quadrant IV, 50°

Quadrant III, 40°

Quadrant II, 70°

Quadrant I, 50°

Answer explanation

For θ = 310°, the angle is in Quadrant IV since it is between 270° and 360°. The reference angle θ' is calculated as 360° - 310° = 50°. Thus, the correct answer is Quadrant IV, 50°.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For θ = 230°, in which quadrant does the terminating ray reside and what is the reference angle θ'?

Quadrant III, 50°

Quadrant II, 40°

Quadrant IV, 50°

Quadrant III, 40°

Answer explanation

For θ = 230°, the angle is in Quadrant III (180° to 270°). The reference angle θ' is found by subtracting 180° from 230°, giving us 50°. Thus, the correct answer is Quadrant III, 50°.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For θ = 100°, in which quadrant does the terminating ray reside and what is the reference angle θ'?

Quadrant II, θ' = 80°

Quadrant I, θ' = 100°

Quadrant III, θ' = 10°

Quadrant IV, θ' = 100°

Answer explanation

For θ = 100°, the angle is in Quadrant II because it is between 90° and 180°. The reference angle θ' is found by subtracting θ from 180°, giving θ' = 180° - 100° = 80°.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For θ = 440°, in which quadrant does the terminating ray reside and what is the reference angle θ'?

Quadrant IV, Reference angle θ' = 60°

Quadrant II, Reference angle θ' = 40°

Quadrant I, Reference angle θ' = 80°

Quadrant III, Reference angle θ' = 100°

Answer explanation

To find the quadrant for θ = 440°, subtract 360° to get 80°, which is in Quadrant I. The reference angle θ' is the acute angle from the x-axis, so θ' = 80°. Thus, the correct answer is Quadrant I, Reference angle θ' = 80°.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For θ = 500°, in which quadrant does the terminating ray reside and what is the reference angle θ'?

Quadrant IV, Reference angle = 30°

Quadrant III, Reference angle = 70°

Quadrant I, Reference angle = 50°

Quadrant II, Reference angle = 40°

Answer explanation

To find the quadrant for θ = 500°, subtract 360° to get 140°, which is in Quadrant II. The reference angle is 180° - 140° = 40°. Thus, the correct answer is Quadrant II, Reference angle = 40°.

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