
Introduction to VSEPR Theory and molecular shape
Authored by Dana Martens
Chemistry
11th Grade
NGSS covered
Used 1+ times

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24 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which of the following best describes the shape of a molecule with two bonding pairs and no lone pairs on the central atom according to VSEPR theory?
Trigonal planar
Linear
Tetrahedral
Bent
Answer explanation
According to VSEPR theory, a molecule with two bonding pairs and no lone pairs on the central atom adopts a linear shape. This arrangement minimizes repulsion between the bonding pairs, resulting in a straight line.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the bond angle in a perfect tetrahedral molecule?
Answer explanation
In a perfect tetrahedral molecule, the bond angles are approximately 109.5°. This geometry arises from the repulsion between four equivalent bonding pairs of electrons, maximizing their distance from each other.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Linear
Trigonal planar
Trigonal pyramidal
Tetrahedral
Answer explanation
Ammonia (NH3) has a central nitrogen atom bonded to three hydrogen atoms and one lone pair of electrons. This arrangement leads to a trigonal pyramidal geometry due to the repulsion between the lone pair and bonding pairs.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the bond angle in a molecule with a trigonal planar geometry?
Answer explanation
In a trigonal planar geometry, the bond angles are 120 degrees. This arrangement allows for optimal spacing between the three bonding pairs of electrons, minimizing repulsion according to VSEPR theory.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which of the following molecules has a bent shape?
Answer explanation
The molecule H2O has a bent shape due to the two lone pairs on the oxygen atom, which repel the hydrogen atoms. In contrast, CO2, CH4, and BF3 have linear or trigonal planar shapes.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
0
1
2
4
Answer explanation
In the linear molecule CO₂, the central carbon atom forms two double bonds with oxygen atoms. Since all valence electrons are used in bonding, there are 0 lone pairs on the central atom.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Tetrahedral
Trigonal planar
Trigonal pyramidal
Bent
Answer explanation
The geometry of BF3 is trigonal planar because it has three bonding pairs of electrons around the central boron atom and no lone pairs, resulting in a flat, triangular shape.
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