Introduction to VSEPR Theory and molecular shape

Introduction to VSEPR Theory and molecular shape

11th Grade

24 Qs

quiz-placeholder

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Introduction to VSEPR Theory and molecular shape

Introduction to VSEPR Theory and molecular shape

Assessment

Quiz

Chemistry

11th Grade

Hard

NGSS
HS-ESS2-6, MS-PS1-1, HS-PS1-2

Standards-aligned

Created by

Dana Martens

Used 1+ times

FREE Resource

24 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following best describes the shape of a molecule with two bonding pairs and no lone pairs on the central atom according to VSEPR theory?

Trigonal planar

Linear

Tetrahedral

Bent

Answer explanation

According to VSEPR theory, a molecule with two bonding pairs and no lone pairs on the central atom adopts a linear shape. This arrangement minimizes repulsion between the bonding pairs, resulting in a straight line.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the bond angle in a perfect tetrahedral molecule?

Answer explanation

In a perfect tetrahedral molecule, the bond angles are approximately 109.5°. This geometry arises from the repulsion between four equivalent bonding pairs of electrons, maximizing their distance from each other.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Linear

Trigonal planar

Trigonal pyramidal

Tetrahedral

Answer explanation

Ammonia (NH3) has a central nitrogen atom bonded to three hydrogen atoms and one lone pair of electrons. This arrangement leads to a trigonal pyramidal geometry due to the repulsion between the lone pair and bonding pairs.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the bond angle in a molecule with a trigonal planar geometry?

Answer explanation

In a trigonal planar geometry, the bond angles are 120 degrees. This arrangement allows for optimal spacing between the three bonding pairs of electrons, minimizing repulsion according to VSEPR theory.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following molecules has a bent shape?

Answer explanation

The molecule H2O has a bent shape due to the two lone pairs on the oxygen atom, which repel the hydrogen atoms. In contrast, CO2, CH4, and BF3 have linear or trigonal planar shapes.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

0

1

2

4

Answer explanation

In the linear molecule CO₂, the central carbon atom forms two double bonds with oxygen atoms. Since all valence electrons are used in bonding, there are 0 lone pairs on the central atom.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tetrahedral

Trigonal planar

Trigonal pyramidal

Bent

Answer explanation

The geometry of BF3 is trigonal planar because it has three bonding pairs of electrons around the central boron atom and no lone pairs, resulting in a flat, triangular shape.

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